3 years ago

Find 3 consecutive even integers such that twice the 3rd is 4 more than triple the 1st

Mathematics

1 answer:

RoseWind [281]3 years ago

5 0

<span>Let n, n+2, and n+4 represent the three consecutive even integers.</span>

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FromTheMoon [43]

Area : Multiply the two numbers

13*8=104 yd^2

Perimeter: Add the two numbers two times

Perimeter : 13+8+13+8=42 yd

Answer:

Area is 104yd^2

Perimeter is 42yd

8 0

4 years ago

What is the probability that you and your friend are both chosen?

WINSTONCH [101]

Answer: $\frac{2}{35}$

Step-by-step explanation:

Given: The total number of ways of to choose 3 contestants out of 7 (including me and my friend)=35..................> Total outcomes.

Favorable outcomes = 2

Then the probability that me and my friend are both chosen = $\frac{\text{favorable outcomes }}{\text{Total outcomes}}$

Thus , the probability that me and my friend are both chosen = $\frac{2}{35}$

5 0

4 years ago

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What is the principle for f)? The math is Simple Interest

Tamiku [17]

See the attachment °_° I hope it helps :-)

8 0

3 years ago

Use the equation c = k + 2 to find the value of c when k = 8.

11111nata11111 [884]

Answer:

Step-by-step explanation:

c=k+2

c=8+2

c=10

6 0

3 years ago

The area of a circle varies directly as the square of its radius. A circle with radius 2 in. Has area 12.568 in.^2 . What is the

Dafna11 [192]

Answer:

$A_2=128.69\ in^2$

Step-by-step explanation:

The area of a circle varies directly as the square of its radius.

$A=\pi r^2$

If r₁ = 2in, A₁ = 12.568 in₂, r₂ = 6.4 in, A₂ = ?

ATQ,

$\dfrac{A_1}{A_2}=\dfrac{r_1^2}{r_2^2}\\\\A_2=\dfrac{A_1r_2^2}{r_1^2}\\\\A_2=\dfrac{12.568 \times 6.4^2}{2^2}\\\\=128.69\ in^2$

So, the new area of the circle is $128.69\ in^2$ .

3 0

3 years ago