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Advocard [28]
3 years ago
6

Lines m and n are parallel 70° a с d n Find the missing angle measures Enter your answers in the boxes ​

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0
A is 110, B is 70, C is 110, D is 70, G is 110, E is 110, and F is 70
You might be interested in
Given the 5th term is 103 and the come differences is -6 2/3 what is the 6th term?
LekaFEV [45]

Answer:

  102 1/3

Step-by-step explanation:

To find the 6th term, add the common difference to the 5th term:

  103 + (-6 2/3) = 102 1/3

6 0
4 years ago
Tomorrow, Mrs. Wendel's class will be using toothpicks for a science project. Each student must use at least 5 toothpicks for th
Amiraneli [1.4K]

Answer:

I'm pretty sure A but let me know if I'm wrong

7 0
3 years ago
Which expressions are equivalent to -3(2+7) A: -6+21 or B:-21+6​
Neporo4naja [7]

<u>Answer:</u>

None

<u>Explanation:</u>

-3(2+7) = -3×9 = -27

-6+21 = 15

-21+6​ = -15

Hence there is no equivalence

3 0
3 years ago
Let U1, ..., Un be i.i.d. Unif(0, 1), and X = max(U1, ..., Un). What is the PDF of X? What is EX? Hint: Find the CDF of X first,
Kryger [21]

Answer:

E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}

Step-by-step explanation:

A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".

We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).

If we select a value x \in (0,1) we want this:

max(U_1, ....,U_n) \leq x

And we can express this like that:

u_i \leq x for each possible i

We assume that the random variable u_i are independent and P)U_i \leq x) =x from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:

P(X \leq x) = P(U_1 \leq 1, ...., U_n \leq x) \prod P(U_i \leq x) =\prod x = x^n

And then cumulative distribution would be expressed like this:

0, x \leq 0

x^n, x \in (0,1)

1, x \geq 1

For each value x\in (0,1) we can find the dendity function like this:

f_X (x) = \frac{d}{dx} F_X (x) = nx^{n-1}

So then we have the pdf defined, and given by:

f_X (x) = n x^{n-1} , x \in (0,1)  and 0 for other case

And now we can find the expected value for the random variable X like this:

E(X) =\int_{0}^1 s f_X (x) dx = \int_{0}^1 x n x^{n-1}

E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}

6 0
3 years ago
7.
nika2105 [10]

Answer:

B. {–3, 5.9, 8.3}

Step-by-step explanation:

The domain is the set of all the values of  

x .The range is the set of all the values of  y .

Domain: { 3.2 , 7.6 , 1.4 , − 9.1 }

Range: { − 3 , 5.9 , 8.3 }

Answer:

range is -3, 5.9 , 8.3

Step-by-step explanation:

{(3.2, –3), (7.6, 5.9), (1.4, –3), (–9.1, 8.3)}

We are given with set of ordered pairs (x,y)

In each ordered pair, x is the domain and y is the range

for domain , take all the x  values (first number) from the ordered pairs

for range, take all the y value (second number) from the ordered pairs

y values of the ordered pairs are -3, 5.9, -3, 8.3

So range is -3, 5.9 , 8.3

3 0
3 years ago
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