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erastova [34]
3 years ago
13

A bag contains 10 red marbles .15 yellow marbles, 5 Green marbles and 20 blue marbles. Five marbles are drawn from the bag. what

is the approximate probability that exactly 2 of the five are blue?
Mathematics
1 answer:
mash [69]3 years ago
7 0

Answer:

c

Step-by-step explanation:

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Solve:<br><br> -11 2/3 x (-4 1/5) = ?
dimaraw [331]

Answer:

Step-by-step explanation:

-35/2 x (-21/5)

-7/2 x (-21/1)

-7/2 x (-21) = 147/2= 78 1/2

4 0
3 years ago
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SPAM IN THE QUESTION COMMENTS free points to :)
Semenov [28]

Answer:

Thank youuuuuu

Step-by-step explanation:

4 0
3 years ago
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The dimensions of a rectangular crate are 6 feet, 8 feet, and 10 feet. What is the<br> volume?
Dafna1 [17]

Answer:

480

Step-by-step explanation:

The formula is L*W*H

6*8*10=480

8 0
2 years ago
What is the multiplicative rate of change of the function shown on the graph? Express your answer in decimal form. Round to the
allsm [11]
In linear models there is a constant additve rate of change. For example, in the equation y = mx + b, m is the constanta additivie rate of change.


In exponential models there is a constant multiplicative rate of change.


The function of the graph seems of the exponential type, so we can expect a constant multiplicative exponential rate.


We can test that using several pair of points.


The multiplicative rate of change is calcualted in this way:

 [f(a) / f(b) ] / (a - b)

Use the points given in the graph: (2, 12.5) , (1, 5) , (0, 2) , (-1, 0.8)

[12.5 / 5] / (2 - 1) = 2.5


[5 / 2] / (1 - 0) = 2.5


[2 / 0.8] / (0 - (-1) ) = 2.5


Then, do doubt, the answer is 2.5





6 0
3 years ago
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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
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