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2 years ago

What is an equivalent fraction of 10/12

Mathematics

2 answers:

pantera1 [17]2 years ago

7 0

Answer:

$\huge \frac{10}{12} = \frac{10 \div 2}{12 \div 2} = \frac{5}{6}$

<h2>5/6 is the right answer.</h2>

BARSIC [14]2 years ago

6 0

Answer:

5/6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

We can simplify this fraction down further by divide both numerator and denominator by 2:

10/2 = 5

12/2 = 6

5/6 will be equivalent to 10/12

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2 years ago

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2 years ago

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4 0

3 years ago

Read 2 more answers

Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.

andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

The equation is given as: $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

6 0

3 years ago