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IrinaVladis [17]

2 years ago

14

Demetrius received his phone bill in the mail. The bill was for $99.00 and the sales tax was 4.5%. He ended up paying $94.54 for

his bill.
True
or
False

1 answer:

Margaret [11]2 years ago

3 0

Answer:

false

Step-by-step explanation:

i think the answer is false srry if i am wrong

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40 POINTS THERE IS MORE THAN 1 ANSWER BRAINLIEST IF CORRECT

mash [69]

Answer:

Whole numbers are also integers. There are other integers which are the opposites of the whole numbers (−1, −2, −3, ...). These negative numbers lie to the left of 0 on the number line. Integers are the whole numbers and their opposites.

4 0

3 years ago

NEED HELP ON THIS PLEASE! Oregon Trail: Percents.

harina [27]

1845-1846

118->148

148-118 = 30 = change

percent

30/118 ≈ 25.4%

1846-1847

148->139

148-139 = 9 = change

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9/148 ≈ 6%

1847-1848

139->151

151-139 = 12 = change

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12/139 ≈ 8.6%

Hope this helped :)

5 0

2 years ago

Write an equation of the parabola with the vertex (-5,4) and focus (-5,0)

ch4aika [34]

Answer:

-0.4 or -10.4

Step-by-step explanation:

5 0

2 years ago

Based on aâ poll, among adults who regret gettingâ tattoos, 18â% say that they were too young when they got their tattoos. Assum

Sergeeva-Olga [200]

Answer:

a) 20.44% probability that none of the selected adults say that they were too young to get tattoos.

b) 35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c) 56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d) No

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they say they were too young when they got their tattoos, or they don't say that. Each adult is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

18% say that they were too young when they got their tattoos.

This means that $p = 0.18$

Eight adults who regret getting tattoos are randomly selected

This means that $n = 8$

a. Find the probability that none of the selected adults say that they were too young to get tattoos.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{8,0}.(0.18)^{0}.(0.82)^{8} = 0.2044$

20.44% probability that none of the selected adults say that they were too young to get tattoos.

b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{8,1}.(0.18)^{1}.(0.82)^{7} = 0.3590$

35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c. Find the probability that the number of selected adults saying they were too young is 0 or 1.

Either a. or b.

20.44 + 35.90 = 56.34

56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d. It we randomly select 9 adults. Is 1 a significantly low number who day that they were too young to get tattoos?

Now $n = 9$

It is significantly low if it is more than 2.5 standard deviations below the mean.

The mean is $E(X) = np = 9*0.18 = 1.62$

The standard deviation is $\sqrt{V(X)} = \sqrt{n*p*(1-p)} = \sqrt{9*0.18*0.82} = 1.15$

1 > (1.62 - 2.5*1.15)

So the answer is no.

5 0

3 years ago

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→[infinity]

Fynjy0 [20]

Answer:

$\lim_{x\rightarrow \infty}(\frac{5x-3}{5x+2})^{5x+1}=e^{-5}$

Step-by-step explanation:

We are given that

$\lim_{x\rightarrow \infty}(\frac{5x-3}{5x+2})^{5x+1}$

When substitute limit x tends to infinity then it is $1^{\infty}$ which is indeterminant form

Wheny= $\lim_{x\rightarrow \infty} f(x)^{g(x))$

and $1^{\infty}$

Then use $y=e^{\lim_{x\rightarrow \infty} g(x)(f(x)-1)}$

We have g(x)=5x+1 and f(x)= $\frac{5x-3}{5x+2}$

Substitute the values in the formula

$y=e^{\lim_{x\rightarrow \infty}(5x+1)(\frac{5x-3}{5x+2}-1)}$

$y=e^{\lim_{x\rightarrow \infty}(\frac{-5(5x+1)}{5x+2})}$

$y=e^{\lim_{x\rightarrow \infty}(\frac{-5(1+\frac{1}{5x})}{1+\frac{2}{5x}})}$

$y=e^{-5}$

$\frac{1}{\infty}=0$

6 0

3 years ago