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kirill [66]
3 years ago
6

Find if there was a mistake in the students work.

Mathematics
2 answers:
fomenos3 years ago
7 0
B would be the answer. hope it helps !
Alexus [3.1K]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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Original Price<br> Percent of Discount<br> Sale Price<br> $82<br> $65.60
expeople1 [14]

Answer:

1.25

Step-by-step explanation:

8 0
3 years ago
Write the equation of a vertical line that passes through the point (3, -3)
lianna [129]
Hello 
<span>the equation of a vertical line that passes through the point (3, -3) is : x = 3 </span>
4 0
3 years ago
Read 2 more answers
Complete the table<br><br> Please help meee
alukav5142 [94]

Answer:

3^{1} - 3

3² - 9

3³ - 27

3^{4} - 81

3^{5} - 243

3^{6} - 729

3^{7} - 2,187

7 0
2 years ago
Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e
svet-max [94.6K]

ANSWER

y = 2x -4

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

x = 5 +  ln(t)

y =  {t}^{2}  + 5

From the first equation we make t the subject to get;

x - 5 =  ln(t)

t =  {e}^{x - 5}

We put it into the second equation.

y =  { ({e}^{x - 5}) }^{2}  + 5

y =  { ({e}^{2(x - 5)}) }  + 5

We differentiate to get;

\frac{dy}{dx}  = 2 {e}^{2(x - 5)}

At x=5,

\frac{dy}{dx}  = 2 {e}^{2(5 - 5)}

\frac{dy}{dx}  = 2 {e}^{0}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5)

y = 2x - 10 + 6

y = 2x -4

Without eliminating the parameter,

\frac{dy}{dx}  =  \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }

\frac{dy}{dx}  =  \frac{ 2t}{  \frac{1}{t} }

\frac{dy}{dx}  =  2 {t}^{2}

At x=5,

5 = 5 +  ln(t)

ln(t)  = 0

t =  {e}^{0}  = 1

This implies that,

\frac{dy}{dx}  =  2 {(1)}^{2}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5) =

y = 2x -4

5 0
3 years ago
Using a number cube and a
victus00 [196]

Answer:

1/12

Step-by-step explanation:

The probability of landing on tail = 1/2

The probability of rolling a 3 = 1/6

The probability of doing BOTH is 1/2 x 1/6 = 1/12

5 0
3 years ago
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