What exactly do you need help on?
Answer:
pay for something and get money from ATM
Step-by-step explanation:
<h2>
Answer with explanation:</h2>
Rolle's Theorem states that:
If f is a continuous function in [a,b] and is differentiable in (a,b)
such that f(a)=f(b)
Then there exist a constant c in between a and b i.e. c∈[a,b]
such that: f'(c)=0
Here we have the function f(x) as:
where x∈[-1,3]
- Since the function f(x) is a polynomial function hence it is continuous as well as differentiable over the interval [-1,3].
Also,
f(-1)=15
(Since,
)
and f(3)=15
( Since,
)
Hence, there will exist a c∈[-1,3] such that f'(c)=0

Hence, the c that satisfy the conclusion is: c=1
Answer:
Step-by-step explanation:
so first make an equation...
10x=2x-32
then do distributive property
10x-2x=2x-32-2x
8x=-32
then divide negative 32 by 8
x= negative 4
The expression without using absolute value is 2z - 11
<h3>Absolute value of a function</h3>
Given the expression with absolute value expressed as:
lz-6l-lz-5l
Since absolute function can both be negative or positive, hence;
lz-6l-lz-5l = z - 6 - -(z - 5)
lz-6l-lz-5l = z-6-(-z+5)
lz-6l-lz-5l = z - 6 + z - 5
lz-6l-lz-5l = 2z - 11
Hence the expression without using absolute value is 2z - 11
Learn more on absolute value here: brainly.com/question/729268
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