Solve for x where xe(0,2pi). state exact answers.

50 points!!!! What is the area of the trapezoid

Deffense [45]

Answer:

308 square feet

Step-by-step explanation:

A = 1/2 (26+18) (14)

A = 1/2 (44) (14)

A = 308

Answer

308 square feet

4 0

2 years ago

Read 2 more answers

A company is designing a new cylindrical water bottle. The volume of the bottle will be 187 cmcubed. The height of the water bot

Simora [160]

Answer:

2.86cm

Step-by-step explanation:

Step 1:

Data obtained from the question. This includes the following:

Volume (V) = 187cm3

Height (h) = 7.3cm

Pi (π) = 3.14

Radius (r) =..?

Step 2:

Determination of the radius of the cylindrical water bottle.

The radius of the cylindrical water bottle can be obtained as follow:

V = πr^2h

187 = 3.14 x r^2 x 7.3

Divide both side by 3.14 x 7.3

r^2 = 187 / (3.14 x 7.3)

Take the square root of both side

r = √[187 / (3.14 x 7.3)]

r = 2.86cm

Therefore, the radius of the cylindrical water bottle is 2.86cm

3 0

2 years ago

I need to show my work for this answer. Solve for x

ale4655 [162]

Answer:

natoooooooy natoooooy natooooy

Step-by-step explanation:

natoooooooy

3 0

2 years ago

The proof that UX ≅ SV is shown. Given: △STU an equilateral triangle ∠TXU ≅ ∠TVS Prove: UX ≅ SV What is the missing statement in

iren2701 [21]

Triangle STU is congruent to triangle UTX is the missing step. AAS (angle-angle-side) is a method of proving 2 triangles congruent, and using the already proved information, you can find the triangles that are congruent by AAS.

6 0

2 years ago

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Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.

marshall27 [118]

Answer:

$\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\ \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right$

Step-by-step explanation:

a) $\lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}$

b) $\lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}$

c) $\lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0$

d) $\lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}$

e) $\lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2$

f) $\lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}$

4 0

2 years ago