The answer is D. Quaternary
Answer:
Explanation:
Oxygen gas and water must be present for iron to rust.
A region of the metal’s surface serves as the anode, where oxidation
occurs:
Fe(s) → Fe²⁺ (aq) + 2 e⁻
The electrons given up by iron reduce atmospheric oxygen to water at the cathode, which is another region of the same metal’s surface:
O₂ (g) + 4H⁺ (aq) + 4 e⁻ → 2 H₂O (l)
The overall redox reaction is:
2 Fe(s) + O₂(g) → 4H⁺(aq) + 2Fe²⁺ (aq) + 2 H₂O(l)
The Fe²⁺ ions formed at the anode are further oxidized by oxygen:
4 Fe²⁺ (aq) + O₂(g) 1 (4 + 2x) H₂O (l) → 2 Fe₂O₃ . xH₂O(s) + 8 H⁺(aq)
This hydrated form of iron(III) oxide is known as rust. The amount of water associated with the iron oxide varies, so we represent the formula as 2 Fe₂O₃ . xH₂O.
The correct size order from the smallest to the largest is:
Animal cell >> Mitochondrion >> Ribosome >> Hexokinase >> ATP >> O2
- The animal cell size is about 20 to 30 micrometers (μm), although it varies according to the type of the cell.
- The average mitochondria size is approximately 0.75 to 3 μm. The size, number, and structure of mitochondria in an animal cell vary according to type of animal cell.
- The ribosome size is approximately 0.02 μm in diameter.
- An enzyme is a macromolecule whose size is variable (its average size is 3–7 nanometers, i.e., 3-7 nm). A micrometer (μm) equal to 1000 nm.
- The adenosine triphosphate or ATP (the energy coin of the cell, which is composed of a five-carbon sugar, three phosphate groups, and adenine) and molecular oxygen (O2) are both simple molecules whose sizes are very small compared to enzymes.
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