What  would  happen  if  M RNA   were  radio actively  labeled  instead  of  polypeptides  is   that    instead  of  one  seeing  the  DNA  passing  through  all  the  molecular  factories  you  will  instead see  just  messenger  RNA   taking  code  and   delivering  it  to  Ribosome.  This  is  mainly  found   in   cytoplasm  and  Endoplasmic  recticulums.
        
             
        
        
        
Answer:
The correct option is;
D. 45%
Explanation:
From the Hardy- Weinberg law, we have;
p² + 2·p·q + q² = 1
p + q = 1
Where:
p = Dom inant allele frequency in the population
q = Recessive allele frequency in the population
p² = The percentage of individuals in the population that are hom ozygous dominant
q² = The percentage of individuals in the population that are homo zygous recessive
2×p×q = The percentage of hete rozyous individuals in the population
The number of individuals that express the recessive phenotype = 86
The number of individuals in the population = 200
The percentage of  individuals that express the recessive phenotype, q² = 86/200 = 0.43
Therefore;
q = √0.43 = 0.656
p + q = 1
p = 1 - q = 1 - 0.656= 0.344
∴ The frequency of  individuals that express the do minant phe notype, p = 0.344
The percentage of heterozyous individuals in the population = 2×p×q × 100 = 2 × 0.656 × 0.344 × 100 = 45.15% ≈ 45%
 
        
             
        
        
        
I'd draw a car on a hill and explain how you press the gas pedal and gravity helps push the car down the hill, or draw it going up the hill and explain how gravity makes it difficult for the car to make it up the hill.
 
        
             
        
        
        
This varieation can be justified because since they had different variations they probably had different niches which led them to evolve differently,this will help because the two species will have no competition
        
             
        
        
        
Answer:
yellow and red offspring will be produced