What would happen if M RNA were radio actively labeled instead of polypeptides is that instead of one seeing the DNA passing through all the molecular factories you will instead see just messenger RNA taking code and delivering it to Ribosome. This is mainly found in cytoplasm and Endoplasmic recticulums.
Answer:
The correct option is;
D. 45%
Explanation:
From the Hardy- Weinberg law, we have;
p² + 2·p·q + q² = 1
p + q = 1
Where:
p = Dom inant allele frequency in the population
q = Recessive allele frequency in the population
p² = The percentage of individuals in the population that are hom ozygous dominant
q² = The percentage of individuals in the population that are homo zygous recessive
2×p×q = The percentage of hete rozyous individuals in the population
The number of individuals that express the recessive phenotype = 86
The number of individuals in the population = 200
The percentage of individuals that express the recessive phenotype, q² = 86/200 = 0.43
Therefore;
q = √0.43 = 0.656
p + q = 1
p = 1 - q = 1 - 0.656= 0.344
∴ The frequency of individuals that express the do minant phe notype, p = 0.344
The percentage of heterozyous individuals in the population = 2×p×q × 100 = 2 × 0.656 × 0.344 × 100 = 45.15% ≈ 45%
I'd draw a car on a hill and explain how you press the gas pedal and gravity helps push the car down the hill, or draw it going up the hill and explain how gravity makes it difficult for the car to make it up the hill.
This varieation can be justified because since they had different variations they probably had different niches which led them to evolve differently,this will help because the two species will have no competition
Answer:
yellow and red offspring will be produced
