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2 years ago

Which of the following inequalities matches the graph?

Mathematics

1 answer:

Mamont248 [21]2 years ago

8 0

Answer:

Step-by-step explanation:

y ≤ 5x - 1

- 5x + y ≤ - 1

5x - y ≥ 1

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Can someone help me with this plzz

topjm [15]

Answer:

Step-by-step explanation:

We can see that the spinner is spun 50 times if we add all the "times spun" up.

7 + 8 + 7 + 8 + 11 + 9 = 50

So if we multiply this by 2, we should get the theoretical probability that 1 will be spun if the spinner was spun 100 times.

1 was spun 7 times when we spun the spinner 50 times, so we can predict that 1 will be spun 14 times if we spin the spinner 100 times.

3 0

3 years ago

Read 2 more answers

The Sahara Desert has an area of approximately 9 400 000 km^2. While estimates of its average depth vary, they center around 150

Andrew [12]

Answer:

a). $1.128\times 10^{25}$ grains

b). $\frac{1}{8000}$

c). $6.54305\times 10^{7}$ years

Step-by-step explanation:

a). Given Sahara desert has an area of approximately = 9400000 km²

= 9400000×(10000000000) cm²

= $9.4\times 10^{16}$ cm²

Depth of the desert = 150 m

= 15000 cm

Volume of desert = Area × Depth

= $9.4\times 10^{16}\times 15000$

= $1.41\times 10^{21}$ cm³

Since 1 cm³ holds sand grains = 8000

Therefore, Grains in Sahara Desert = $1.41\times 10^{21}\times 8000$

= $1.128\times 10^{25}$

b). Since 1 cm³ = 8000 grains

1 grain = $\frac{1}{8000}$ cm³

c). A truck can carry sand = 20.5 m³ Or $20.5\times (10^{2})^{3} cm^{3}$

= $2.05\times 10^{7}$ cm³

Now time taken to recreate Sahara Desert = $\frac{\text{Total amount of sand}}{\text{Sand in one truck}}\times 30$ seconds

= $\frac{1.41\times 10^{21}}{2.05\times 10^{7}}\times 30$

= $20.6341463\times 10^{14}$ seconds

= $\frac{20.6341463\times 10^{14} }{365\times \times 24\times 3600}$ years

= $6.54305\times 10^{7}$ years

6 0

3 years ago

Round to the nearest hundredth

Artist 52 [7]

They are already rounded?; unless you need to round lower

8 0

2 years ago

If f(x) = x2 + 2x – 1, find f(1).<br> Answer:

Alina [70]

Answer:

f(1)= (1)^2+ 2(1) -1

= 2

7 0

3 years ago

Read 2 more answers

Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩

klemol [59]

$\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle$

$\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt$

$\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle$

$\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1$

$\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2$

$\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3$

With the initial condition $\mathbf r(0)=\langle4,6,3\rangle$ , we find

$\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9$

$\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6$

$\dfrac92\cdot0^2+C_3=3\implies C_3=3$

So the particular solution to the IVP is

$\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle$

4 0

3 years ago

Which of the following inequalities matches the graph? ​

Which of the following inequalities matches the graph?