Answer:
Step-by-step explanation:
a=180-122=58°
Let ABC be the triangle in which BC is diameter.
Diameter always make angle 90° on the circumference.
so b=90°
∠B=1/2×58=29°
29+b+c=180
29+90+c=180
c=180-119=61°
Given
x^5*k=a .................(1)
x^2*k=b .................(2)
We need to find x^3.
Solution:
On inspection, we note that (1)/(2) gives x^3 on the left hand side, but the division is valid on conditions that x ≠ 0 and k ≠ 0.
So we conclude:
(1) / (2)

=>

=>
on condition that
and
The answer should be the third one I believe
I am pretty sure the answer is 13
1. N=x+3
S=2(x+3), or Sam=2x+6