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Strike441 [17]
3 years ago
13

4(c-3)=8 what does c equals? correct answers ONLY please

Mathematics
2 answers:
rodikova [14]3 years ago
5 0
Is there like a picture or something?
emmainna [20.7K]3 years ago
5 0

Answer:

the answer is this 4(c-3)=8 is c=5

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Jay wants to rent a metal detector. A rental company charges a one-time fee of $15 plus $2 per hour to rent a metal detector. Ja
user100 [1]

Step-by-step explanation:

$15 initial fee. $2 per hour. $35 limit.

35 - 15 = 20

After the initial fee, he has $20 left.

20 ÷ 2 = 10

He can rent the metal detector for 10 hours.

4 0
3 years ago
Unit 6 homework 2 need help
kodGreya [7K]

∆PQR and ∆SQT are similar, so corresponding sides occur in fixed ratios with one another. This means

SQ / PQ = ST / PR

Solve for x :

8 / ((x + 5) + 8) = (x - 9) / 21

8 / (x + 13) = (x - 9) / 21

168 = (x - 9) (x + 13)

168 = x² + 4x - 117

x² + 4x - 285 = 0

(x + 19) (x - 15) = 0

⇒   x = -19   or   x = 15

But x can't be smaller than 9, otherwise ST = x - 9 would be a negative length. So x = 15.

8 0
2 years ago
What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)
dedylja [7]

<u>Answer:</u>

32 units

<u>Step-by-step explanation:</u>

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

B (-3,0)

C (1,0)

D (1,-6)

AB = \sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100} = 10 units

BC = \sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16} = 4 units

CD = \sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36} = 6 units

AD = \sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144} = 12 units

Perimeter of ABCD = 10+4+6+12 = 32 units

6 0
3 years ago
How to turn 8/20 into a percent
Katarina [22]
<span>8/20 * 100 = 0.4 * 100 = 40% </span>
3 0
3 years ago
Read 2 more answers
What is the constant of variation, k, of the direct variation, y=kx, through (5,8)
miv72 [106K]

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (\stackrel{x}{5}~,~\stackrel{y}{8})\qquad \implies 8=k(5)\implies \cfrac{8}{5}=k

6 0
3 years ago
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