Answer:
Javier's parents set aside $1500 when he was born
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:

In which E is the interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
In this question, we have that:

We have to find P. So




Javier's parents set aside $1500 when he was born
Y = ln {[sin(x)]^2}
use the chain rule
y' = 1 /[sin(x)]^2 * 2sin(x)*cos(x) = 2cos(x) / sin(x) = 2 cot(x)
Answer: 2 cot(x)
Answer:
The attached graph shows my answer.
Step-by-step explanation:
The graph has to start at the top because the number of carrots has to decrease and the graph slants down to the right because the time has to increase. Then the situation says that he eats one carrot at a time until <u>half</u> are eaten. The graph shows the line going down until approximately half. Then he doesn't eat any more, so the line is horizontal until the end of the graph to show no change.
Answer:
The final answers are x = 10.385 OR x = -0.385
Step-by-step explanation:
Given the equation is x^2 -4 = 10x
Rewriting it in quadratic form as:- x^2 -10x -4 = 0.
a = 1, b = -10, c = -4.
Using Quadratic formula as follows:- x = ( -b ± √(b² -4ac) ) / (2a)
x = ( 10 ± √(100 -4*1*-4) ) / (2*1)
x = ( 10 ± √(100 +16) ) / (2)
x = ( 10 ± √(116) ) / (2)
x = ( 10 ± 10.77 ) / (2)
x = ( 10 + 10.77 ) / (2) OR x = ( 10 - 10.77 ) / (2)
x = 20.77/2 OR x = -0.77/2
x = 10.385 OR x = -0.385
Hence, final answers are x = 10.385 OR x = -0.385
Answer:
We are 95% sure that the true proportion of students that supports a fee increase is between 0.75 and 0.85.
Step-by-step explanation:
The interpretation of a x% confidence interval of proportions being between a and b is that:
We are x% sure that the true proportion of the population is between a and b.
If the 95% confidence interval estimating the proportion of students supporting the fee increase is (0.75; 0.85), what conclusion can be drawn
We are 95% sure that the true proportion of students that supports a fee increase is between 0.75 and 0.85.