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So hmm, if you notice the picture below
"y" would be the opposite to the 10° angle, and "x" would its adjacent
Reno is "y" north and "x" west from Miami
solve for "y", to see how much north
and
solve for "x" to see how much west
make sure, that in both cases, your calculator is in Degree mode, since the angle is in degrees, as opposed to Radian mode
now... for the section B)
if notice the Reno-Miami line, and you were to draw a North line through it, anywhere in between, or at an endpoint like the in the picture at Reno, the "clockwise" angle, will always be the same, 100°
bear in mind ( no pun intended ), that Bearings use the North line, and the clockwise angle from it, as in the picture below
"y" would be the opposite to the 10° angle, and "x" would its adjacent
Reno is "y" north and "x" west from Miami
and
make sure, that in both cases, your calculator is in Degree mode, since the angle is in degrees, as opposed to Radian mode
now... for the section B)
if notice the Reno-Miami line, and you were to draw a North line through it, anywhere in between, or at an endpoint like the in the picture at Reno, the "clockwise" angle, will always be the same, 100°
bear in mind ( no pun intended ), that Bearings use the North line, and the clockwise angle from it, as in the picture below
Answer:
Step-by-step explanation:
a.
y=0.75x
y-y1=(y2-y1)/(x2-x1)×(x-x1)
y-3=(6-3)/(8-4) (x-4)
y-3=3/4(x-4)
y-3=3/4 x-3
y=3/4 x-3+3
y=3/4 x
if y=f(x)
f(x)=0.75x
c.
f(12)=0.75×12=9$
