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3 years ago

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What is the y-intercept of 2x+5y=−20 ? (0,−4) (10,4) (0,10) (−4,0)

2 answers:

vovangra [49]3 years ago

5 0

Answer:

(0,-4)

Step-by-step explanation:

Just took the quiz

Katen [24]3 years ago

3 0

Okay so for this problem you want to change it to an slope-intercept equation (y=mx+b, where m=slope and b=y intercept). so first you want to subtract 2x from both sides to isolate 5y, which gives you 5y=-2x-20. After that you want to isolate y so you’ll divide both sides by 5. This gives you y=-2/5(x) - 4. because b is the y-intercept and -4=b, then the y-intercept is -4. from here you need to know that coordinates are listed as (x, y) so the y-intercept is where x is equal to 0. So the answer is (0,-4). Does that make sense?

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How many x-intercepts does the graph of y = 4x^2-12x+9 have?

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1. In the figure below ABC∡=153°, ABD∢=(5x+5)°, and DBC∢=(3x+12)°. Find the measure of ABD∢ and DBC∢. Show all work

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By angle addition postulate,

m(∠ABD) + m(∠DBC) = m(∠ABC)

Now substitute the values of each angle,

(5x + 5)° + (3x + 12)° = 153°

Combine like terms of the expression,

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Substitute the value of 'x' to get the measure of each angle,

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2 years ago

What is the equation of the circle with center (5,-4) and containing the points (5,-2)

gtnhenbr [62]

Answer:

The equation of a circle is $(x-5)^2+(y+4)^2=4$ .

Step-by-step explanation:

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$(x-h)^2+(y-k)^2=r^2$ (where center is $(h,k)$ , the point $(x_{1},y_{1})$ and the radius known as $r$ ).

-Use the center (5,-4) and the point (5,-2) for the equation:

$(5-5)^2+(-2+4)^2=r^2$

-Solve the equation:

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$\sqrt{4} = \sqrt{r^2}$

$2 = r$

-After you found the radius, use the center (5, -4) and radius 2 to get the equation of a circle:

$(x-5)^2+(y+4)^2=2^2$

-Then, after you have the equation, the radius needs to simplified by the exponent:

$(x-5)^2+(y+4)^2=4$

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