Find the value of x. 64 100 XE

How do i multiply a whole number by an improper fraction?

klemol [59]

Exactly the same way you would do it if it were a proper fraction . . .
multiply the numerator by the whole number, and then clean up
the fraction.

4 0

4 years ago

Read 2 more answers

Given the function defined in the table below, find the average rate of

AURORKA [14]

Answer:

Average rate of change = $\frac{2}{5}$

Step-by-step explanation:

Average rate of change of a function 'f' in the interval a ≤ x ≤ b is given by,

Average rate of change = $\frac{f(b)-f(a)}{b-a}$

We have to find the average rate of change in the interval 20 ≤ x ≤ 65

From the table attached,

f(65) = 32

f(20) = 14

Average rate of change = $\frac{32-14}{65-20}$

= $\frac{18}{45}$

= $\frac{2}{5}$

Therefore, average rate of change in the given interval is $\frac{2}{5}$ .

7 0

3 years ago

Help x3 4 1/4 + __________ = 7 1/2

yulyashka [42]

Answer:

4 1/4 + 3 1/4 = 7 1/2

Step-by-step explanation:

To make 1/4 to 1/2 You would need 1/4, because 2/4 make 1/2

7-4= 3 so therefore you would have 3 1/4

7 0

4 years ago

Write an equation of the line passing through (2,4) and (3,5). Give the answer in standard form.

saveliy_v [14]

The answer to waht you are looking for is: x-y=-2

6 0

4 years ago

A random sample of ten 2011 sports cars is taken and their city mileage is recorded. The results are as follows: 20 21 25 21 21

serious [3.7K]

Answer:

$ME = 1.833 * \frac{4.367}{\sqrt{10}}= 2.531$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=24.8$

The sample deviation calculated $s=4.367$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,9)".And we see that $t_{\alpha/2}=1.833$

And the margin of error would be given by:

$ME = 1.833 * \frac{4.367}{\sqrt{10}}= 2.531$

5 0

4 years ago