Ask question

Ask question

All categories

3 years ago

11

In a class of students, the following data table summarizes how many students play an instrument or a sport. What is the probabi

lity that a student plays a sport given that they play an instrument?

1 answer:

hjlf3 years ago

3 0

8 students out of 27

the total of students is 27 out of the 27 students 19 dont play and instrument and a sport

You might be interested in

Money that is collecting interest in a bank account doubles in value every 10 years.

MArishka [77]

C . 2 to the power of 9

6 0

3 years ago

Which of the following measures cannot be determined from a box plot?

ad-work [718]

<h3>3 Answers:</h3>

B) Mean
C) Mean absolute deviation
E) Mode

==========================================================

Explanation:

The box plot, aka "box-and-whisker plot", visually represents five things. These things are:

Minimum
Q1 = first quartile
Median (sometimes referred to as Q2 or second quartile)
Q3 = third quartile
Maximum

This list of five items is known as the five number summary.

The min is the tip of the left most whisker, assuming there aren't any small outliers. The max is the opposite side, being the tip of the right most whisker (assuming no large outliers). If there are any outliers, then they'll be shown as "island" dots on their own separated from the main box plot. The left and right edges of the box are Q1 and Q3 respectively. The median is the vertical line inside the box. The vertical line does not have to be at the midpoint of the left and right edges of the box. It simply needs to be somewhere in the box.

--------

Since the box plot lets us know the min and max, we can compute the range because

range = max - min

and we can also calculate the interquartile range (IQR) because

IQR = Q3 - Q1

--------

So to summarize so far, the five number summary is visually represented as the box plot. The range and IQR can be computed using items from the five number summary.

We cannot compute the mean because we would need the actual data set of values, rather than the summary data. The same goes for the mean absolute deviation (MAD) and the mode. Since your teacher is looking for things that cannot be determined from a box plot, we'll go for answers B, C and E.

In other words, we rule out choices A, D, and F because we can compute or determine those values from a box plot.

7 0

3 years ago

A chemical factory has 2 cylindrical chemical tanks, one containing Chemical X and the other containing Chemical Y. The tank con

Mashutka [201]

The tank with Chemical X "takes up" a space of 25ft³. Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume. The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:
$\frac{25}{1.5}=\frac{1.5V}{1.5} \\16 \frac{2}{3}=V$
To find the volume of a cylinder, we find the base area and multiply by the height. We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:
$16 \frac{2}{3}=3.2h \\ 16 \frac{2}{3}=3 \frac {2}{10}h$
We would now divide both sides by 3 2/10:
$\frac{16 \frac{2}{3}}{3 \frac{2}{10}}= \frac{3 \frac{2}{10}h}{3 \frac{2}{10}}$
This is the same as:
$\frac{\frac{50}{3}}{\frac{32}{10}}=h \\ \\ \frac{50}{3}* \frac{10}{32}=h \\ \\ \frac{500}{96}$
So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.

8 0

3 years ago

I will give brainliest.

butalik [34]

17, you only have to add up a few because of the x and y placements. Hope this helps you :)

4 0

3 years ago

Read 2 more answers

Sao can text 1500 words per hour. He needs to text a message with 85 words. He only has 5 minutes between classes to complete th

Amiraneli [1.4K]

First divide 1500 by 60 to see how many words he can write in a minute. he can text 25 words a minute. multiply that by five to see how many words he can text in five minutes. he can text 125 words in five minutes, so he can text 85 words in a minute.

The answer is yes.

5 0

3 years ago

Read 2 more answers