6V + 2(V+12) = 488
8V = 464
V = 58 mph for 6 hours
V+12=70 mph for 2 hours.
check: 58*6 = 348
70*2 = 140
348 +140 =488
the car was traveling at 70 mph on the 2nd highway
Answer:
270.9 ft
Step-by-step explanation:
6 + 300sin(62)
= 270.8842779 ft
Answer:
(a) 93.19%
(b) 267.3
Step-by-step explanation:
The population mean and standard deviation are given as 502 and 116 respectively.
Consider, <em>X</em> be the random variable that shows the SAT critical reading score is normally distributed.
(a) The percent of the SAT verbal scores are less than 675 can be calculated as:
![P(X](https://tex.z-dn.net/?f=P%28X%3C675%29%3DP%28Z%3C%5Cfrac%7B675-502%7D%7B116%7D%29%5C%5C%20P%28X%3C675%29%3DP%28Z%3C%5Cfrac%7B675-502%7D%7B116%7D%29%5C%5CP%28X%3C675%29%3DP%28Z%3C1.49%29%5C%5CP%28X%3C675%29%3D%200.9319)
Thus, the required percentage is 93.19%
(b)
The number of SAT verbal scores that are expected to be greater than 575 can be calculated as:
![P(X>575)=P(\frac{x-502}{116}>\frac{575-502}{116}\\P(X>575)=P(Z>\frac{575-502}{116})\\P(X>575)=P(Z>0.6293)\\P(X>575)=0.2673](https://tex.z-dn.net/?f=P%28X%3E575%29%3DP%28%5Cfrac%7Bx-502%7D%7B116%7D%3E%5Cfrac%7B575-502%7D%7B116%7D%5C%5CP%28X%3E575%29%3DP%28Z%3E%5Cfrac%7B575-502%7D%7B116%7D%29%5C%5CP%28X%3E575%29%3DP%28Z%3E0.6293%29%5C%5CP%28X%3E575%29%3D0.2673)
So,
Out of 1000 randomly selected SAT verbal scores, 1000(0.2673) = 267.3 are expected to have greater than 575.
<span>180>3x+24>90
-24 -24
156>3x>66
/3 /3 /3
52>x>22
possible values of x are any number greater than 22, but less than 52 </span>