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posledela
3 years ago
9

In the first football game, the quarterback completed 18 out of 24 passes he attempted.

Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

A) 75%

B) 74%

Step-by-step explanation:

A) 18/24=0.75

B) 37/50= 0.74

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PLEASE HELP! I'm struggling on questions like this one. If you can please help on other questions but that's up to you! I will g
Setler79 [48]

Answer:

y=3/2x+3

Step-by-step explanation:

the line hits the y-axis at 3 so b=3 and the change in y is up 3 and the change in x is to the right 2 so the change in y over the change in x is 3/2

7 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
2 years ago
WORTH 15 POINTS PLEASE ANSWER ASAP! IF IT LETS ME MARK YOU BRAINLIST I WILL!
masya89 [10]

Answer:

the answer is 3/8

Step-by-step explanation:

multiply 9/10 by 5/12 then you get the answer 3/8

8 0
2 years ago
Read 2 more answers
The sum of three times a number d and 5 is 17?
andre [41]

Answer:

3 times 4 + 5 = 17

Step-by-step explanation:

3d+5=17

    -5  -5

________

3d = 12

__  __

3     3

d = 4  

7 0
3 years ago
What is the domain of -2
Free_Kalibri [48]
The answer is 7x so I this helps you please thank me plz bye
5 0
2 years ago
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