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marshall27 [118]

3 years ago

13

If cyclist travels the average rate of 24 miles per day how many days will it take the cyclist totravel 600 miles?

1 answer:

yarga [219]3 years ago

5 0

600*24= 25

It would take the cyclist 25 days to travel 600 miles.

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There are twenty trays of paint. Each tray has five colors. One of the colors is purple. What fraction of the colors is purple i

suter [353]

In one tray, we have 1/5. Since one is purple out of the 5 colors.

So in 20 trays, we have:

(1/5) x 20 = 20/5 = 4

6 0

3 years ago

Read 2 more answers

The perimeter of a playing field for a certain sport is 334ft. The field is a rectangle, and the length is 47 ft longer than the

babunello [35]

Answer:

The dimensions of the rectangle = 60ft by 107ft

Where 60 ft = Width of the playing field

107ft = Length of the playing field

Step-by-step explanation:

A playing field is Rectangular is shape, hence,

The formula for Perimeter of a rectangle = 2(L + W)

P = 334 ft

L = 47 + W

W = W

Hence we input these values in the formula and we have:

334 = 2(47 + W + W)

334 = 2(47 + 2W)

334 = 94 + 4W

334 - 94 = 4W

240 = 4W

W = 240/4

W = 60

There fore, the width of this playing field = 60 ft

The length of this rectangle is calculated as:

47 + W

47 + 60

= 107 ft

The length of this playing field = 107ft

Therefore the dimensions of the rectangle = 60ft by 107ft

6 0

3 years ago

P(×)= x(2x + 1)- 6x-3 <br>Factorize p(×)

kherson [118]

Step-by-step explanation:

P(X)=2x²-5x-3 is in the form ax²+bx+c

Using quadratic equation

x={-b±√(b²-4ac)}/2a

x=3,-1/2

4 0

3 years ago

If the integral of the product of x squared and e raised to the negative 4 times x power, dx equals the product of negative 1 ov

Nataly_w [17]

Answer:

$A + B + E = 32$

Step-by-step explanation:

Given

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C$

Required

Find $A +B + E$

We have:

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C$

Using integration by parts

$\int {u} \, dv = uv - \int vdu$

Where

$u = x^2$ and $dv = e^{-4x}dx$

Solve for du (differentiate u)

$du = 2x\ dx$

Solve for v (integrate dv)

$v = -\frac{1}{4}e^{-4x}$

So, we have:

$\int {u} \, dv = uv - \int vdu$

$\int\limits {x^2\cdot e^{-4x}} \, dx = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx$

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx$

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx$

-----------------------------------------------------------------------

Solving

$\int xe^{-4x} dx$

Integration by parts

$u = x$ ---- $du = dx$

$dv = e^{-4x}dx$ ---------- $v = -\frac{1}{4}e^{-4x}$

So:

$\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx$

$\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx$

$\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}$

So, we have:

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx$

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}]$

Open bracket

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x} -\frac{1}{8}e^{-4x}$

Factor out $e^{-4x}$

$\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}$

Rewrite as:

$\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}$

Recall that:

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C$

$\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}$

By comparison:

$-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2$

$-\frac{1}{8}x = -\frac{1}{64}Bx$

$-\frac{1}{8} = -\frac{1}{64}E$

Solve A, B and C

$-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2$

Divide by $-x^2$

$\frac{1}{4} = \frac{1}{64}A$

Multiply by 64

$64 * \frac{1}{4} = A$

$A =16$

$-\frac{1}{8}x = -\frac{1}{64}Bx$

Divide by $-x$

$\frac{1}{8} = \frac{1}{64}B$

Multiply by 64

$64 * \frac{1}{8} = \frac{1}{64}B*64$

$B = 8$

$-\frac{1}{8} = -\frac{1}{64}E$

Multiply by -64

$-64 * -\frac{1}{8} = -\frac{1}{64}E * -64$

$E = 8$

So:

$A + B + E = 16 +8+8$

$A + B + E = 32$

4 0

3 years ago

A line goes through the points (7,8) and (3, 10). What is the slope of the line?

nekit [7.7K]

Answer:

$slope = m = -\dfrac{1}{2}$

Step-by-step explanation:

$slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$slope = m = \dfrac{10 - 8}{3 - 7}$

$slope = m = \dfrac{2}{-4}$

$slope = m = -\dfrac{1}{2}$

6 0

4 years ago