Yoshi has a rope 30 feet long. He must cut it in pieces that are 1/4 foot long will he get more or fewer than 30 pieces

Teesha is in the chess club. There are 31 students in the club. Four of them will be picked at random to attend an awards banque

tamaranim1 [39]

Teesha chances are 4/31

6 0

3 years ago

Suppose you are going to graph the data in the table below. What data should be represented on each axis and what should the inc

Greeley [361]

Independent variable on x-axis (value you can choose) dependent variable on y-axis (corresponding value for the value you have chosen) You can the hours and the distance traveled is a function of those hours. also, I'd go in increments of 5. More accurate than increments of 15. The answer is D! <span><span>
Hope this helps!</span></span>

4 0

3 years ago

The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo

Aloiza [94]

Answer:

$a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]$

Step-by-step explanation:

a. -Given that:

$n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64$

#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:

$\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03$

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator, $\bar x_m-\bar x_f$ is calculated by the following following:

$\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

-And the margin of error, E at a 99% confidence can be calculated as:

$E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416$

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

$\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:

$CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]$

Hence, the 99% confidence interval is [51.2884,82.7716]

7 0

2 years ago

Lloyd is making goblins and elves on a video game. It takes 6 rounds to make a goblin and 8 rounds to make an elf. If he complet

marusya05 [52]

Answer:

24 rounds

Step-by-step explanation:

This question has to do with a factor of numbers which we refer to as:

Lowest common multiple.

Lowest common multiple can be defined as the Lowest multiple that is common to the multiple of two numbers.

We are told in the question that:

Lloyd is making goblins and elves on a video game. It takes 6 rounds to make a goblin and 8 rounds to make an elf.

We find the multiples of 6 and 8

6 = 1, 6, 12, 18, 24, 48, 54, 60, 66, 72 e.tc.

8 = 1, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, e.t.c

The Lowest Common Multiple: This is the least or lowest multiple that is common to both 6 and 8

= 24.

Therefore, it will take 24 rounds for Lloyd to complete another goblin and elf at the same time

4 0

2 years ago

What is 9/10 as hundredths in fraction form and decimal form?

Arte-miy333 [17]

Answer:

see below

Step-by-step explanation:

9/10

To get as a fraction over 100, multiply the top and bottom by 10

9*10 90

------ = ------------

10*10 100

9/10 = 90/100

The decimal form for 9/10 is .9 and for 90/100 is .90

5 0

2 years ago