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Gnesinka [82]
3 years ago
13

Find the distance between the two points. (-6, – 7), (0,0)

Mathematics
1 answer:
Elden [556K]3 years ago
8 0

Answer:

√85

Step-by-step explanation:

for this, you will probably need to draw a graph. Plot the points, and then you will notice that you can draw a triangle with one side being the x-axis ( go on to (-6,0) then drop down unitll you hit the point (-6;-7)

// use the pythagoream theorem to find the length

the distance of the leg on the x-axis is 6  (calculate 0-(-6))

the distance of the leg that is dropping down is -7 (calculate 0-(-7))

then we have 2 legs and need to find the hypotenuse.

Pythagorean theorem a^2 + b^2 = c^2

substitute :

6^2 + 7^2 = c^2

36+49 = 85

c= √85

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Step-by-step explanation: Using the volume of a cylinder calculator, I got the answer of 4712.3889803847 centimeters, but rounded it to the nearest hundreth. Hope this helps!

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Mia has 12 boxes of cookies. Each box contains 36 cookies. she has another 258 cookies in the pantry. How many cookies does she
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690

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2 years ago
For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.
Flauer [41]

 

\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\

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\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276

.

\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}    

 

 

8 0
3 years ago
There were 20 boys and 20 girls in a chorus. What is the ratio of boys to girls
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Step-by-step explanation:

3 0
2 years ago
Jack and Jill live 126 km apart. They want to leave their homes at the same time,
Digiron [165]

Answer:

Both will leave their homes to meet on time at 9 am  

Step-by-step explanation:

Given as, Distance between Jack  and Jill = 126 km

Speed of Jack rides = 18 kilometers per hours

Speed of Jill rides     = 24 kilometers per hours

Let the distance travel by Jack = x km

And the distance travel by Jill  =  (126 - x ) km

Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So,     x = 18 × T

And  126 - x = 24 × T

Or,    126 - x =  24 × \frac{x}{18}

Or,    126 - x =  x × \frac{4}{3}

Or,    378 - 3x = 4x

Or,    378 = 7x

i.e x = \frac{378}{7} = 54 km

And distance travel by Jill = 126 - 54 = 72 km

So, time taken by Jack = \frac{x}{18} = \frac{54}{18}

Or, Time taken by Jack = 3 hours

Similarly Time take by Jill = \frac{72}{24} = 3 hours

∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

Hence, Both will leave their homes to meet on time at 9 am   Answer

7 0
3 years ago
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