To solve this problem you must apply the proccedure shown below:
1. You have:
Sinα=opposite/hypotenuse
α=62°
opposite=x
hypotenuse=15 ft
2. When you substitute the values into Sinα=opposite/hypotenuse, you obtain:
Sinα=opposite/hypotenuse
Sin(62°)=x/15
3. You must clear "x", as below:
x=(15)(Sin(62°))
x=13.24 ft
The answer is. 13.24 ft
Answer:

So it would takes approximately 6.9 hours to reach 32 F.
Step-by-step explanation:
For this case we have the following differential equationÑ

We can reorder the expression like this:

We can use the substitution
and
so then we have:

IF we integrate both sides we got:

If we apply exponential in both sides we got:

And if we replace w = u-T we got:

We can also express the solution in the following terms:

For this case we know that
since w ehave a cooloing,
, we have this model:
And if we want that the temperature would be 32F we can solve for t like this:



If we apply natural logs on both sides we got:


So it would takes approximately 6.9 hours to reach 32 F.
The expression (n+3) represents the measure of an exterior angle of a regular octadecagonal.
24/.375 = 64, the answer is no.