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AVprozaik [17]
3 years ago
14

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -36 and 2304, respectively

Mathematics
1 answer:
Eva8 [605]3 years ago
3 0
a_5=ra_4=r^2a_3=r^3a_2
2304=-36r^3\implies r=-4

Since a_2=ra_1\implies -36=-4a_1\implies a_1=9, the sequence takes the form

a_n=(-4)^{n-1}a_1=9(-4)^{n-1}
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8 0
3 years ago
Given that f(x)=-3x+9, what is f(4)?
timurjin [86]

Answer:

F(4) = -3

Step-by-step explanation:

First, you would plug in 4 for x. PEMDAS, so you would multiply -3 and 4, giving you -12. Then add 9, which gives you -3.

6 0
2 years ago
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2. Find the 20th term of an arithmetic sequence if its 6th term is 14 and 14th term is 6.
Fudgin [204]

Answer:

\sf t_{20}= 0

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

      \sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }

6th term is 14 ⇒ \sf t_6 = 14

                a + (6 - 1)d = 14

                    a  +  5d = 14  --------------(I)

14th term is 6 ⇒\sf t_{14} = 6

             a + (14-1)d = 6

                  a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

        (I)          a + 5d = 14

        (II)         a + 13d = 6

                    <u>-    -          -</u>

                            -8d = 8

                               d  = 8 ÷(-8)      

                              \sf \boxed{\bf d= (-1)}

Plugin d = -1 in equation (I)

a + 5(-1) = 14

      a -5  = 14

             a = 14 + 5

             \sf \boxed{\bf a = 19}  

20th term:

 \sf t_{20}= 19 + 19*(-1)

       = 19 - 19

   \sf \boxed{\bf t_{20} = 0}

8 0
1 year ago
Read 2 more answers
Find the x-intercept and the y-intercept without graphing. Write the coordinates of each intercept.
ANEK [815]

Answer:

Point of x-intercept: (2,0).

Point of y-intercept: (0,6).

Step-by-step explanation:

1. Finding the x-intercept.

This point is where the graph of the function touches the x axis. It can be found by substituting the "y" for 0. This is how you do it:

y=-3x+6\\ \\-3x+6=0\\ \\-3x=-6\\\\x=\frac{-6}{-3} \\ \\x=2

Hence, the point of x-intercept: (2,0).

2. Finding the y-intercept.

This point is where the graph of the function touches the y axis. It can be found by substituting the "x" for 0. This is how you do it:

y=-3(0)+6\\ \\y=6

Hence, the point of y-intercept: (0,6).

7 0
1 year ago
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Evaluate 16^1/2 x 2^-3<br> Give your answer as a fraction in its simplest form.
kati45 [8]
Your answer would be 1/2
6 0
3 years ago
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