Answer:
HJVJKN ,KMN,. MN
Step-by-step explanation:
Answer:
Step-by-step explanation:
Area of circle = 78.5 in²
πr² = 78.5
3.14*r² = 78.5

r = 5 in
Answer: $9
Step-by-step explanation: The maturity value of a loan is the total amount you must repay, including the principal and any interest you incur. The term of the loan is the time for which it has been granted.
Answer:
Therefore it is possible to find the circumference and area of a circle if we are given the radius or diameter of the circle.
Step-by-step explanation:
i) to find the area of a circle or circumference the radius , r, is required.
ii) if we are given the diameter, d. then we have to find the radius, r, by dividing the diameter by 2, that is
.
iii) area of the circle is given by A = 
iv) circumference of the circle is given by C = 
Therefore it is possible to find the circumference and area of a circle if we are given the radius or diameter of the circle.
Answer: You should cut out squares that are 4 inches by 4 inches.
One of the ways to do this problem is write and graph an equation. We can write an equation for the volume of this shape and then use a graphing calculator to graph it. If we look where the graph crosses 440, we will have our solution.
The volume needs to be 440. If we let x equal the side of the square that is cut out, we have the following dimensions.
Length = 19 - 2x
Width = 18 - 2x
Height = x
Volume = LWH
So our equation could be: y = (19 - 2x)(18 - 2x)x
If you graph that equation, it will intersect at the point (4, 440). Therefore, our square could be 4 by 4 inches.