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3 years ago

Long cooks three Vietnamese dinners that weigh a total of 40 ounces. What is the average(mean) weight for each dinner?

Mathematics

1 answer:

asambeis [7]3 years ago

8 0

Answer:

The average (mean) weight for each dinner is 13.33 oz.

Step-by-step explanation:

mean = sum of all data points / total number of items in the set

mean = 40 / 3

mean = 13.33 oz

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be rectangular prism and rectangular pyramid have the same volume. determine the value of x, the height of the pyramid.

Marina CMI [18]

ANSWER

$x= 9 \: in$

EXPLANATION

The volume of a rectangular prism is given by the formula,

$V = l \times b \times h$
We substitute the dimensions to obtain,

$V = 6 \times 3 \times 12 \: {in}^{3}$

The volume of the rectangular pyramid is,

$V = \frac{1}{3} \times 6 \times 12 \times x \: {in}^{3}$

Equating the two volumes gives,

$\frac{1}{3} \times 6 \times 12 \times x = 6 \times 3 \times 12$

We divide through by 6×12 to get,

$\frac{x}{3}=3$

We solve for x to obtain,

$x = 3 \times 3$

$x = 9 \: in$

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SVEN [57.7K]

Answer:

$\boxed{\sf distance \: between \: the \: objects \: \: is \: 2.5 \: cm}$

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

the product of their masses, given by standard formula.

$A = G \cdot \frac{m_1.m_2}{ {d}^{2} }$

where A,d & G are force of attraction, distance of separation & proportionality constant respectively.

Given:

A1 = 2 units

d1= 5 cm

A2 = 8 units

To find:

Distance of separation when the force of attraction is 8 units d2 = ?

Solution:

Substituting the given values in above at each point,

$A_1 = G \cdot \frac{m_1.m_2}{ {d_1}^{2} } \\ 2 = G \cdot \frac{m_1.m_2}{ {5}^{2} } \\ \sf similarly \: at \: second \: point \: of \: attraction \\ A_2 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ 8 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ \sf \: \: dividing \: both \: of \: the \: equation \\ \frac{2}{8} = \frac{G \cdot \frac{m_1.m_2}{ {5}^{2} }}{G \cdot \frac{m_1.m_2}{ {d_2}^{2} } } \\ \sf \: G \: m_1 and \: m_2 \: are \: \: constant \: hence \\ \sf they \: can \: be \: cancelled \: out \\ \frac{2}{8} = \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } } \\ \sf rearranging \: above \: equation \\ \frac{1}{4} = \frac{{d_2}^{2} }{ {5}^{2} } \\ {d_2}^{2} = \frac{ {5}^{2} }{4 } \\ {d_2}^{2} = \frac{25}{4} \\ {d_2}^{2} = 6.25 \\ \sqrt{{d_2}^{2} } = \sqrt{6.25} \\ \boxed{ \sf{d_2} = 2.5 \: cm}$

Answer: the distance between the two objects is 2.5 cm, if the attraction between them is 8 units.

Learn more about universal law of gravitation here brainly.com/question/27244479

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tankabanditka [31]

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Step-by-step explanation:

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