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GREYUIT [131]
2 years ago
14

I quite don’t get this question and I have 4 minutes remaining

Mathematics
1 answer:
gregori [183]2 years ago
7 0

The length of one of the sides of the larger pentagon is 24 cm. The length of one of the sides of the smaller pentagon is 8 cm.

24÷8=3

So, if the larger pentagon is 3x the size of the smaller pentagon, we can find the area of the smaller pentagon by dividing the area of the larger pentagon by 3.

135÷3=45

The area of the smaller pentagon is 45in²

<em>Hope this helps! Pwease mark me brainliest! Have a great day!</em>

<em />

<em>−xXheyoXx</em>

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8^x times 2^(4-x) = 1<br> Find x.<br> With detailed steps.
Dafna1 [17]

Answer: x= -1

Step-by-step explanation:

In mathematics when you have bases that are the same while multiplying you add the powers. In this case we do not have the same bases so we are going to make it look like 8 is 2. So we sort of simplify it. So we get 8 and put into like 2^4. We do not eliminate the power x that was already there though. So we will have 2^4x × 2^4-x. So like I said earlier we add the powers. Soo we will have

  1. 4x +4-x
  2. 4x-x=1
  3. 3x+4-4 =1-4
  4. 3x/3 = -3/3
  5. x= -1
<h2>Hope that helped!</h2>
7 0
2 years ago
ABC is an isosceles triangle: AC = 13cm. What is the length of AB?
sveticcg [70]
  • AB=AC

AC=13cm

\\ \sf\longmapsto AB

\\ \sf\longmapsto AC

\\ \sf\longmapsto 13cm

5 0
2 years ago
13. Find the slope of the line that contains (3, 1) and (1, 1).
Mumz [18]

Answer:

slope would be zero

Step-by-step explanation:

It is not moving on the graph

Hope this helps!

5 0
3 years ago
11 NEED HELP ASAP WILL GIVE BRAINLY
fomenos

Answer:

the second answer seems to be the most reassonable

Step-by-step explanation:

3 0
3 years ago
Regular hexagon FGHIJK shares a common shares a common center with square ABCD on a coordinate plane .
timurjin [86]

Answer:

<h3>"The answer is the yellow lines in the attached figure. </h3>

Step-by-step explanation: As shown in the attached figure, regular hexagon FGHIJK and square ABCD shares common centre on the co-ordinate plane and AB || FG.

We are to find the line across which the combined figure will reflect onto itself.

In the attached figure, we see two lines which are yellow in colour. We can easily detect that the figure will be reflected onto itself if these two lines acts as a mirror separately.

Hence these yellow lines are the required lines."

<h3><u>Hope this helps!</u></h3>

6 0
3 years ago
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