Question

What is the percent by mass (mv) of a solution with 1.56 g of benzene dissolved in gasoline to make 998.44 mL of solution? (density of gasoline = 0.7489 g/mL)
please I need help lol

Answer 1

Answer:

The percentage by mass of benzene in the solution is approximately 0.2%

Explanation:

The given parameters are;

The mass of the benzene solute dissolved in the gasoline solvent, m₁ = 1.56 g

The total volume of the benzene gasoline solution made, V = 998.44 mL

The density of gasoline, ρ = 0.7489 g/mL

Mass, m = Density, ρ × Volume, V

∴ The mass of gasoline in the 998.44 mL, solution = 0.7489 g/mL × 998.44 mL = 747.731716 g

The total mass of the solution = The mass of the benzene in the solution + The mass of the gasoline in the solution

∴ The total mass of the solution = 747.731716 g + 1.5 g = 749.231716 g

$The \ percentage \ by \ mass = \dfrac{The \ mass \ of \ a \ fraction}{(The \ mass \ of \ the \ total \ solution)} \times 100$

The percentage by mass of benzene in the solution = (1.5 g/749.231716 g)×100 ≈ 0.2% by mass.