What amount of heat energy is required to raise the temperature of 152 g of water from 24 °C to 74 °C.
1 answer:
Answer:
Q = 31798.4J = 31.79kJ
Explanation:
Heat energy (Q) = ?
Mass (m) = 152g
T1 = 24°C
T2 = 74°C
Specific heat capacity of water (c) = 4.184J/g°C
Q = Mc∇T
Q = 152 * 4.184 * (74 - 24)
Q = 635.968 * 50
Q = 31798.4J
Q = 31.79kJ
Heat required is 31.79kJ
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