The correct answer is A. Urban areas have higher temperatures.
Explanation
Urban Area is a term to refer to cities. Urban areas are characterized by having a developed infrastructure (wide roads, vehicular bridges, wide platforms, tall buildings, residential areas, industrial areas, among others).
Recent studies affirm that urban areas are warmer than surrounding areas; This phenomenon is because the materials with are built buildings, roads, houses, and others, concentrate the sun's rays, increasing the temperature of cities. In addition, the lack of trees deepens this phenomenon, because the trees contribute to cooling by physicochemical processes such as evapotranspiration.
According to the above, it is possible to affirm that urban areas are hotter than their surrounding area because they lack vegetation, and the materials with which it is built contribute to the increase in temperature.
On the other hand, urban areas are characterized by habitat fragmentation, more problems with soil erosion, and less rain infiltration into the soil.
Learn more in: brainly.com/question/23587978
Answer:
mass of Uranus: 9.31x10^22 kg
Explanation:
As I stated in the comments, the question in this problem is to calculate the mass of Uranus, given it's conditions.
Now, we have the data of the atmosphere gases, but for calculations, this data is irrelevant.
To calculate the mass of Uranus, we can use the second law of Newton which is:
F = m * a (1)
In this case, the only Force exerting here would be the weight so:
F = m * g (2)
And the force of Uranus, can also be expressed in terms of pressure and Area so:
F = P * S (3)
Now, if we replace (3) in (2) we have:
P * S = m * g
Solving for m:
m = P * S / g (4)
We have all the data, therefore, let's replace it in the above expression to calculate the mass of Uranus:
m = 1x10^8 * 8.1x10^15 / 8.7
m = 9.31x10^22 kg
This is the mass of Uranus
First, you need to know 1 kg = 10^3 g. And 1 m^3 = 10^6 m^3. So the 1 g/cm3 = 10^3 kg/m3. So the answer is 1.93*10^4 kg/m3.
There are no options i can select from.
Li+ have<span> more</span> elements i think