The measure of angle of ∠BAM (θ) will be 9°. Then the correct option is D.
<h3>What is trigonometry?</h3>
The connection between the lengths and angles of a triangular shape is the subject of trigonometry.
ABCD is a rectangle with AB = 3BC.
And M is the mid-point of BC.
2BM = BC
Then the tangent of angle of ∠BAM (θ) will be
tan θ = (BM) / (AB)
tan θ = (BM) / (3BC)
tan θ = (BM) / (3 × 2BC)
tan θ = 1/6
θ = tan⁻¹ (1/6)
θ = 9.46°
θ ≅ 9°
Then the correct option is D.
More about the trigonometry link is given below.
brainly.com/question/22698523
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Answer:
B
Step-by-step explanation:
subtract 1/3 from both sides
m< -2 7/12
Answer:
84.5
Step-by-step explanation:
multiply score by number of students, add them, divide by total students.
(1)
we are given
![\frac{y}{6} =x](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B6%7D%20%3Dx)
we can find for y
multiply both sides by 6
![\frac{y}{6}*6 =6*x](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B6%7D%2A6%20%3D6%2Ax)
![y=6x](https://tex.z-dn.net/?f=y%3D6x)
we can see that y is directly proportional to x
so, option-D........Answer
(2)
y varies inversely with x
so, we can write it as
![y=k\frac{1}{x}](https://tex.z-dn.net/?f=y%3Dk%5Cfrac%7B1%7D%7Bx%7D)
now, we are given
y=5 when x=2.5
so, we can plug it here
![5=k\frac{1}{2.5}](https://tex.z-dn.net/?f=5%3Dk%5Cfrac%7B1%7D%7B2.5%7D)
and then we can solve for k
![5*2.5=2.5*k\frac{1}{2.5}](https://tex.z-dn.net/?f=5%2A2.5%3D2.5%2Ak%5Cfrac%7B1%7D%7B2.5%7D)
![k=12.5](https://tex.z-dn.net/?f=k%3D12.5)
now, we can plug back
![y=\frac{12.5}{x}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B12.5%7D%7Bx%7D)
we can plug x=20
![y=\frac{12.5}{20}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B12.5%7D%7B20%7D)
.............Answer
(3)
we are given
The current, I, in a circuit varies inversely with the resistance, R
so, we can write it as
![I=\frac{k}{R}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7Bk%7D%7BR%7D)
we have R=12 when I=3
so, we can plug it
![3=\frac{k}{12}](https://tex.z-dn.net/?f=3%3D%5Cfrac%7Bk%7D%7B12%7D)
now, we can solve for k
![3*12=12*\frac{k}{12}](https://tex.z-dn.net/?f=3%2A12%3D12%2A%5Cfrac%7Bk%7D%7B12%7D)
![k=36](https://tex.z-dn.net/?f=k%3D36)
now, we can plug back
![I=\frac{36}{R}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B36%7D%7BR%7D)
we can plug R=6
![I=\frac{36}{6}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B36%7D%7B6%7D)
................Answer