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Ghella [55]
3 years ago
10

Model the following problem with a quadratic equation. Then solve. Find the length of a side of a square with an area of 75 ft2.

Model the problem with a quadratic equation. Let x be the length of a side of the square.
Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

x = 8.6603 m

Step-by-step explanation:

If x is the length of a side of the square, the area of the square will be x^2.

So, if the area of the square is 75 ft2, we can formulate the quadratic equation:

x^2 = 75

Now, solving the equation, we just need to make the square root of 75:

x = sqrt(75) = ±8.6603

x1 = 8.6603

x2 = -8.6603

Now, as x represents the length of a side of the square, and measurements can't be negative, we take only the positive value, so:

x = 8.6603 m

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ANEK [815]

Answer:

The side length is 11 inches

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

1331 in ^3 = s^3

Take the cube root of each side

(1331 in ^3 ) ^1/3  = s^3 ^ 1/3

11 in = s

3 0
3 years ago
The cost of a computer is $849. The store is offering a 20% discount and a sales tax of 6% is added after the discount. What is
givi [52]
$849-20%=$679
$679+6%(sales tax)=$719
$719 is the total cost of the tv
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3 years ago
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How much simple interest rate would earn if had $10,000 and you were being paid 5% for 15 months?
lakkis [162]
Here is the interest equation: I=prt
Where I is interest, p is principal, r is rate and t is time(in years).
Substitute with known values.

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4 0
3 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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3 years ago
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Rina8888 [55]

M = 21 - R is our equation. Plug your value of 12 into the equation for R.

M = 21 - 12.

M = 9.

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