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hammer [34]
2 years ago
10

2 planes leave the airport at the same time. their speeds are 140 mph and 170 mph and the angle between their courses is 25 degr

ees. how far apart are they after 2.5 hours
Mathematics
1 answer:
Damm [24]2 years ago
5 0

Answer:

183.27miles

Step-by-step explanation:

Note that we are considering two planes.

Plane 1

Speed = 140 mph

Time = 2.5 hours

Distance = ?

Speed = distance/time

140 mph = distance/2.5hrs

Distance = 140×2.5

= 350miles

Plane 2

Speed = 170 mph

Time = 2.5 hours

Distance = ?

Speed = distance/time

170 mph = distance/2.5hrs

Distance = 170×2.5

= 425miles

The angle between side is 25 degree

From cosine rule

c^2 = a^2 + b^2 − 2abcos(tetha)

Where a = 350

b = 425miles

c^2 = 350^2+425^2-2(350×425)(cos25)

c^2 = 122500+180625-297500(0.906)

c^2 = 303125-269535

c^2 = 33590

C = √33590

C = 183.27miles

The distance they flew apart after 2.5hrs is 183.27miles

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The manager at a golf course found that the population mean length of the holes at the golf courses is 415.9 yd. In this​ context, is the number 415.9 a parameter or a​ statistic?

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