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Bas_tet [7]
3 years ago
8

Is 14 meters greater than or less than 140 centimeters

Mathematics
2 answers:
Marrrta [24]3 years ago
7 0

14 meters is bigger than 140 centimeters
soldier1979 [14.2K]3 years ago
3 0
1 meter=100 centimeters
14 meters=100*14=1400
I multiplied by 100 because I wanted to convert meters to centimeters, so I can compare the numbers.
140 cm<1400 cm
1400 cm=14 meters, and 14 meters wins!

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I need help in this please! thank you so much!
Anna35 [415]

Answer:

C) p(x) has a zero between x=2 and x=4

Step-by-step explanation:

For a polynomial p(x), p(a)=R means that, when p(x) is divided by x-a, the remainder is R.

This is called the remainder theorem

Therefore p(2)=1, p(4)=-1 means that when p(x) is divided x-2 and x-4 is 1 and -1 respectively.

Also the Intermediate value theorem says that, if p(a) and p(b) have opposite signs then there is a certain c on (a,b) where f(c)=0 i.e there is a zero between a and b

Therefore the correct answer is C

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3 years ago
Find the lettered angles.
Zinaida [17]
It’s 59 bro it’s easy
4 0
3 years ago
The larger leg of a right triangle is 2 feet longer than its smaller leg. The hypotenuse is 4 feet longer than the smaller leg.
maks197457 [2]
Hope it helps you:))

7 0
3 years ago
Consider the following sequence
wlad13 [49]

Answer:

a₇ =  2.375

Step-by-step explanation:

There is a common ratio r between consecutive terms, that is

r = \frac{-76}{152} = \frac{38}{-76} = \frac{-19}{38} = - \frac{1}{2}

This indicates the sequence is geometric with nth term

a_{n} = a₁ (r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 152 and r = - \frac{1}{2} , then

a_{n} = 152 (-\frac{1}{2}) ^{n-1} , so

a₇ = 152 (-\frac{1}{2}) ^{6} = 152 × \frac{1}{64} = 2.375

3 0
3 years ago
Read 2 more answers
The graph above is a transformation of the function x2 Write an equation for the function graphed above
lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2)   \ \ \ \  y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \  \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right  \\

We summarize (1) and (3):

2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.

Substitute b=-1 into (2):

9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\

From (5) subtract (4):

8a=4\ |:8\\a=0,5.\ \ \ \  \Rightarrow\\

Substitute a=0,5 into (4):

0,5+c=-1\\c=-1,5.

Hense:

y=0,5x²-x-1,5.

5 0
2 years ago
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