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2 years ago

Simon is painting his garden fence. The fence is 80m long. So far, he has painted 45m. How much does he have left to paint?

Mathematics

1 answer:

lara31 [8.8K]2 years ago

4 0

Answer:

Step-by-step explanation:

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The gravitational force produced between any two objects kept 2.5×10^4 km apart is 580 N . At what distance should they be kept

DochEvi [55]

Answer:

Formula for gravitational force F = G M1 * M2 / R^2 where G is the gravitational constant

F2 / F1 = (R1 / R2)^2 = 1/2 where F2 is the required force

R2 = (2)^1/2 R1 distance for R2 to be 1/2 force at R1

Since force is proportional to the square of the distance of separation, increasing the distance of separation by 2^2 will halve the force

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2 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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2 years ago

What is meant by the term financial planning?

Naily [24]

Answer:

a Long-term goals are reached over an extended period of time, so your current income does not affect

them.

Step-by-step explanation:

Financial planning refers to long term goals that are planned and reached over an extended period of time to keep one solvent in cases of emergency without having a direct effect on current income.

Solvency simply means having more assets than liabilities to be able to stay afloat of one's debts.

8 0

2 years ago

The amount $180.00 is what percent greater than $135.00?

sergiy2304 [10]

Answer:

Its Option C

Step-by-step explanation:

The difference is 180 - 135 = $45

So it is 45 * 100 / 135

= 33.33% greater

4 0

2 years ago

Use the position equation given below, where s represents the height of the object (in feet),

mariarad [96]

The answers to the questions are

The mathematical model is given as s = −16t2 + 1054
The height after 4.5 seconds is 730 feet

the time it would take to strike the ground is 8.11 seconds.

<h3>How to solve for the position of the object</h3>

The mathematical model of this problem would be written as

s = −16t2 + v0t + s0

s0 = 1054

then we would have

s = −16t2 + 1054

b. after 4.5 seconds the height is going to be

s = −16t2 + 1054

= −16(4.5)² + 1054

= -16 * 20.25 + 1054

= 730

C. the time that it takes to strike the ground

s = −16t² + 1054

= 16t² = 1054

t² = 1054/16

= 65.88

t = √65.88

t = 8.11

Hence the time it would take to strike the ground is 8.11 seconds.