2 years ago

What is the solution of the equation?-10 + sqrt x+8 = -4

1 answer:

6 0

$D:x+8\geq0\to x\geq-8\\\\-10+\sqrt{x+8}=-4\ \ \ /+10\\\\\sqrt{x+8}=-4+10\\\\\sqrt{x+8}=6\iff x+8=36\\\\x=36-8\\\\x=28\in D$

You might be interested in

The solids are similar. Find the missing dimensions.

Katyanochek1 [597]

C=15.5
h=8.5
b=14.5
hope this helps

5 0

3 years ago

Read 2 more answers

What's the answer and how do you do it?

Monica [59]

The vertical asymptotes for a rational expression, occur at the values of "x" that make the denominator 0, and therefore the expression undefined.

what are those anyway? simple, just set the denominator to 0, solve for "x", and that will spit them out.

x + 4 = 0
x = -4

there, if "x" ever becomes -4, then the fraction turns to $\bf \cfrac{1}{x+4}\implies \cfrac{1}{-4+4}\implies \stackrel{und efined}{\cfrac{1}{0}}$

thus, that's where the vertical asymptote is at, x = -4.

7 0

2 years ago

Read 2 more answers

The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and

Scorpion4ik [409]

Answer:

$\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)$

Step-by-step explanation:

The PDF of X is

$\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)$

The PDF of Y is

$\bf g(x)=\mu e^{-\mu x}\;(x\geq0)$

The means of X and Y are respectively,

$\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}$

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

$\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)$

7 0

2 years ago

F(x) = 6 (2 – 9), find f-1(x).<br> find the inverse

Tanzania [10]

Try using Symbolab!

4 0

3 years ago

What is the volume of the composite figure?

Stells [14]

The right answer is

D.)

Hope this helps :)