Q(p) = k/p^3 . . . . . . . . we want to find k
q(10) = k/10^3 = 64
k = 64,000
Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3
Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150
Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3
A price of $3 per unit will yield a maximum profit.
we know that
domain is all possible values of x for which any function is defined
so, here domain will be all possible values of x fro which y is defined
so, we will find minimum and maximum value of x
we can see that
x starts from 0
so, minimum value is x=0
and it goes to right upto infinity
so, domain will be
...............Answer
3*x/4=24
3*x= 24*4
3x=96
3x/3=96/3
x=32
Answer:
40 miles
Step-by-step explanation:
At this rate, it travels 80 miles per 2 hours, or 40 miles per 1 hour.
The train's travels 40 miles per hour.