3 years ago

What is the solution to the equation 41/5 =15-(2x+3)

2 answers:

4 0

$\frac{41}{5}=15-(2x+3) \\\\ \frac{41}{5}=15-2x-3 \\\\ \frac{41}{5}=12^{(5}-2x^{(5} \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=\frac{19}{10}}$

Sunny_sXe [5.5K]3 years ago

3 0

$\dfrac{41}{5}=15-(2x+3)\\
\dfrac{41}{5}=15-2x-3\\
\dfrac{41}{5}=12-2x|\cdot5\\
41=60-10x\\
10x=19\\
x=\dfrac{19}{10}
$

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