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mrs_skeptik [129]
4 years ago
11

What is the solution to the equation 41/5 =15-(2x+3)

Mathematics
2 answers:
likoan [24]4 years ago
4 0
\frac{41}{5}=15-(2x+3) \\\\ \frac{41}{5}=15-2x-3 \\\\ \frac{41}{5}=12^{(5}-2x^{(5} \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=\frac{19}{10}}
Sunny_sXe [5.5K]4 years ago
3 0
\dfrac{41}{5}=15-(2x+3)\\
\dfrac{41}{5}=15-2x-3\\
\dfrac{41}{5}=12-2x|\cdot5\\
41=60-10x\\
10x=19\\
x=\dfrac{19}{10}

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Answer:

48 sq. units

Step-by-step explanation:

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But you are aware that, the median of a trapezoid is equal to half the sum of the bases, thus the first part of the formulae  is covered by the median

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Hence area, A, of a trapezoid is simplified to product of median and amplitude

A=amplitude*median\\\\A=6*8=48sq.units

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4 years ago
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For calculating that, you have to find the unit rate first;

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