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Andrej [43]
3 years ago
14

Given lines L1 and L2 and L1 = (1-a)x-y and L2= 6x+ay =9 find the value of a if L1 and L2 are parallel then L1 and L2 are perpen

dicular?​
Mathematics
2 answers:
sammy [17]3 years ago
7 0

Answer:

am not sure pls double check

True [87]3 years ago
4 0

Step-by-step explanation:

\huge{\textbf{\textsf{{\color{skyblue}{an}}{\blue{sw}}{\red{er}} {\color{red}{: }}}}}

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a cell phone company offers two different monthly plans.plan a charges $41 for unlimited cell phone minutes plus $0.10 per text
tiny-mole [99]

41+0.10x = 31+0.15x

10 +0.10x=0.15x

10=0.05x

x=10/.05

x= 200 text messages


check 200*0.10 = 20 +41 =61

200*0.15 = 30+31 = 61

 they equal each other so number of texts is 200

6 0
3 years ago
Tell me w what is the book and notebook​
Oduvanchick [21]

Answer:

a book is something you read a notebook is something you write in.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the factored form of this expression?<br> 9x^2-65y^2
Lesechka [4]

Answer:

Step-by-step explanation:

I suspect it is 64 not 65,

9x^2-64y^2

= (3x - 8y)(3x + 8y).

(If it is 65 there are no factors)

6 0
3 years ago
Read 2 more answers
3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +
klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

3 0
3 years ago
Which expression is equivalent to (p^10r^−5)^1/5 ?
meriva

Answer:

p^2/r

Step-by-step explanation:

An equivalent expression is the expression in simplest form. Here apply exponent rules by multiplying the exponents of each term by 1/5.

(p^{10}r^{-5})^{\frac{1}{5}}\\\\(p^{\frac{10}{5}}r^{\frac{-5}{5}})\\\\p^2r^{-1}\\\\\frac{p^2}{r}

3 0
3 years ago
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