All categories

3 years ago

Find the slope of the lines that go through the following points.

Mathematics

2 answers:

kumpel [21]3 years ago

6 0

Answer:

use the formula y2 - y1 / x2 - x1

inn [45]3 years ago

3 0

Answer:

y2-y1 /x2-x1

Step-by-step explanation:

slope is the same as gradient

follow this principle (x,y)

Gradient (m) =y2-y1 /x2-x1

You might be interested in

Solve each system 9x - 8y = -4 -x - 4y=-24

algol [13]

Thee ansssweeer is. (4,5)

6 0

2 years ago

Read 2 more answers

Plzzz helpppp333332222222222

Sati [7]

Answer: The answer is C or 13 units

How?: by a method called rise over run

the rise is at the y axis and the run is at x axis

*COUNT VERY CAREFULLY*

if you count right you should get 6 as a rise and 7 for run

6+7= 13

5 0

3 years ago

Read 2 more answers

Strawberries cost $2 per pound. Kate buys 5 pounds and gets 20% discount on the total cost. How much does Kate pay for the straw

Tema [17]

The total cost without the discount is given by:

$C = (2) * (5)\\C = 10$ $

Then, to find the discounted amount, we make the following rule of three:

10 $ ------------------> 100%

x ----------------------> 20%

From here, we clear the value of x.

We have then:

$x = (\frac{20}{100}) * (10)\\x = 2$

Then, the cost of the Strawberries with the discount is:

$10 - 2 = 8$ $

Answer:

Kate pays for the strawberries about $ 8.

3 0

3 years ago

Read 2 more answers

Which line segment is a radius of circle F? BE AC AB BF

AlexFokin [52]

I think the best answer is AB

8 0

3 years ago

5. Find the discriminant of 15x2 = 4x – 1 and describe

diamong [38]

Answer:

a) The discriminant of the equation = - 44

b)The nature of the roots will be imaginary.

c) $x = \frac{2 +\sqrt{11} i}{15} or, x = \frac{2 - \sqrt{11} i}{15}$

Step-by-step explanation:

Here, the given expression is $15x^{2} = 4x -1$

or, $15x^{2} - 4x + 1 = 0$

Now the discriminant (D) of a quadratic equation $ax^{2} +b x + c = 0$

D = $b^{2} - 4ac = (-4)^{2} - 4(15) (1) = 16 - (60) = -44$

Hence, the discriminant of the equation = - 44

As D< 0, so the roots will be imaginary.

Now,by quadratic formula : $x = \frac{-b \pm \sqrt{b^{2} - 4ac} }{2a}$

So, here $x = \frac{-(-4) \pm \sqrt{D} }{2a} = \frac{4 \pm \sqrt{(-44 )} }{30}$

So, either $x = \frac{4 + \sqrt{(-44 )} }{30} or, x = \frac{4 - \sqrt{(-44 )} }{30}$

or, $x = \frac{2 +\sqrt{11} i}{15} or, x = \frac{2 - \sqrt{11} i}{15}$

8 0

3 years ago