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harina [27]
2 years ago
6

Rewrite the following equations in the form y=mx + b and identify the values of m and b

Mathematics
1 answer:
arlik [135]2 years ago
5 0
You need to put the equations?
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What is the domain and range please?
Stella [2.4K]
The second graph: y = 3
Domain: all real number
Range: y = 3
7 0
3 years ago
Derivative of tan(2x+3) using first principle
kodGreya [7K]
f(x)=\tan(2x+3)

The derivative is given by the limit

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h

You have

\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}

By this identity, you have

\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}

So in the limit you get

\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}
\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}

The first two limits are both 1, and the single term in the last limit approaches 0 as h\to0, so you're left with

f'(x)=\dfrac12\sec^2(2x+3)

which agrees with the result you get from applying the chain rule.
7 0
3 years ago
Using perfect factors find the square root of 1764
Zolol [24]

The square root of 1764 using perfect factors is 42

<h3>How to determine the square root using perfect factors?</h3>

The number is given as:

1764

Rewrite as

x^2 = 1764

Express 1764 as the product of its factors

x^2 = 2 * 2 * 3 * 3  * 7 * 7

Express as squares

x^2 = 2^2 * 3^2 * 7^2

Take the square root of both sides

x = 2 * 3 * 7

Evaluate the product

x = 42

Hence, the square root of 1764 using perfect factors is 42

Read more about perfect factors at

brainly.com/question/1538726

#SPJ1

3 0
1 year ago
Juan earns $625 per week. He is married and claims 3 withholding allowances. He pays $90 each
atroni [7]

Answer:

what is this

Step-by-step explanation:

7 0
3 years ago
Can anyone help me with thism
maw [93]
The volume of the cuboid is 900 in meters.
4 0
3 years ago
Read 2 more answers
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