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4 years ago

Select the correct answer.

2 answers:

7 0

To answer this question you must know that there is a theorem called the "Two secants angle theorem", which establishes that the measure of an angle formed when two secants intersecting outside the circle is equal to 1/2 the difference of the two intercepted arcs.
Therefore, as you can see, the correct answer is the option B): B)1/2 the difference of the intercepted arcs.

Lyrx [107]4 years ago

4 0

Answer:

(B) ${\frac{1}{2}}$ the difference of the intercepted arcs.

Step-by-step explanation:

Two secants angle theorem: Two secants theorem states that the measure of an angle formed when two secants intersects outside the circle is always equal to ${\frac{1}{2}}$ the difference of the two intercepted arcs.

Therefore, from the theorem of two secants angle, The measure of an angle formed by two secants intersecting outside the circle equals ${\frac{1}{2}}$ the difference of the intercepted arcs.

Hence, option B is correct.

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Notes on isosceles triangles, base angles and notes on the diagonals thanks :D

rjkz [21]

Hey,
In isosceles triangles there r two equal sides .
Base angles is usually used for isosceles triangles ....
Diagonals are two lines which intersect each other...

8 0

3 years ago

Plz look at pic !!!! Plz Help!!! <br> Use proportion to solve

soldi70 [24.7K]

Answer:

It takes 26 2/3 gallons to make a 400 mile trip.

Step-by-step explanation:

This question is simply asking for the number of miles per gallon . In math, <em>per</em> means this is meant to be written as a fraction.

"If a trip of 270 miles required 18 gallons of gas" is actually saying "270 miles per 18 gallons." This can be written as a fraction like so: 270/18.

If we're looking for the amount of gas used for a 400 mile trip, we have the fraction: 400/g, g being the amount of gallons it took to make that trip.

Now we can set up the proportion: $\frac{270}{18} =\frac{400}{g}$

Cross multiply and solve accordingly.

$\frac{270}{18} =\frac{400}{g}$

400 $270g = 400 *18\\ 270g = 7200\\g=26\frac{2}{3}$ /g

So the answer is:

It takes 26 2/3 gallons to make a 400 mile trip.

6 0

4 years ago

(50 points and Brainiest

Scorpion4ik [409]

could you possibly make two zoomed in pictures?

its quite hard to see

7 0

3 years ago

Find the derivative of f(x) = 12x^2 + 8x at x = 9.

zvonat [6]

Answer:

224

Step-by-step explanation:

We will need the following rules for derivative:

$(f+g)'=f'+g'$ Sum rule.

$(cf)'=cf'$ Constant multiple rule.

$(x^n)'=nx^{n-1}$ Power rule.

$(x)'=1$ Slope of y=x is 1.

$f(x)=12x^2+8x$

$f'(x)=(12x^2+8x)'$

$f'(x)=(12x^2)'+(8x)'$ by sum rule.

$f'(x)=12(x^2)+8(x)'$ by constant multiple rule.

$f'(x)=12(2x)+8(1)$ by power rule.

$f'(x)=24x+8$

Now we need to find the derivative function evaluated at x=9.

$f'(9)=24(9)+8$

$f'(9)=216+8$

$f'(9)=224$

In case you wanted to use the formal definition of derivative:

$f'(x)=\lim_{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}$

Or the formal definition evaluated at x=a:

$f'(a)=\lim_{h \rightarrow 0} \frac{f(a+h)-f(a)}{h}$

Let's use that a=9.

$f'(9)=\lim_{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}$

We need to find f(9+h) and f(9):

$f(9+h)=12(9+h)^2+8(9+h)$

$f(9+h)=12(9+h)(9+h)+72+8h$

$f(9+h)=12(81+18h+h^2)+72+8h$

(used foil or the formula (x+a)(x+a)=x^2+2ax+a^2)

$f(9+h)=972+216h+12h^2+72+8h$

Combine like terms:

$f(9+h)=1044+224h+12h^2$

$f(9)=12(9)^2+8(9)$

$f(9)=12(81)+72$

$f(9)=972+72$

$f(9)=1044$

Ok now back to our definition:

$f'(9)=\lim_{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}$

$f'(9)=\lim_{h \rightarrow 0} \frac{1044+224h+12h^2-1044}{h}$

Simplify by doing 1044-1044:

$f'(9)=\lim_{h \rightarrow 0} \frac{224h+12h^2}{h}$

Each term has a factor of h so divide top and bottom by h:

$f'(9)=\lim_{h \rightarrow 0} \frac{224+12h}{1}$

$f'(9)=\lim_{h \rightarrow 0}(224+12h)$

$f'(9)=224+12(0)$

$f'(9)=224+0$

$f'(9)=224$

8 0

3 years ago

Which of the following statements is true

kolbaska11 [484]

Answer:

D. This quadratic equation two complex solutions.

Step-by-step explanation:

$5x^2 +6x +2= 0\\$

Equating it with

$ax^2 +bx +c= 0\\$

a = 5, b = 6, c = 2

$b^2 -4ac\\= 6^2 - 4\times 5\times 2\\= 36-40\\b^2 -4ac= - 4\\$

$\because b^2 -4ac$ is negative.

Therefore, this quadratic equation two complex solutions.

5 0

3 years ago