An introductory psychology class has 9 freshman males, 15 freshman females, 8 sophomore males, and 12 sophomore females. A rando
m sample of n = 2 students is selected from the class. If the first student in the sample is a male, what is the probability that the second student will also be a male?
now n= 2 so first student was male so one male student was taken out of the equation so 16 male left. now left male students by remaining students so now total left students = 43
so, prob = remaining males/remaining students=16/43
So if its 1-10, and you can either roll a 1 or 2, it would be 2/10, then simplified to 1/5, and in order to get the answer you need to multiply it by 60
1/5 x 60/1 = 12
(sorry if I got it wrong, feel free to correct me if I did)
and positive numbers are greater than 
