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sergey [27]
3 years ago
11

−4.2(−2.8+4.5)​ I think I know what the answer is but I just want to be 100% sure. Please solve this and tell me your answer. I

would really appreciate it. Thanks!
Mathematics
1 answer:
Talja [164]3 years ago
7 0

Answer:

-7.14

Step-by-step explanation:

Evaluate

−4.2(−2.8 + 4.5)​

Open parenthesis

(-4.2 * -2.8) + (-4.2 * 4.5)

= (11.76) + (- 18.9)

= 11.76 - 18.9

= -7.14

NOTE:

Negative (-) × negative (-) = positive (+)

Positive (+) × positive (+) = positive (+)

Negative (-) × positive (+) = negative (-)

Positive (+) × negative (-) = negative (-)

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64 pints is 8 gallons

Step-by-step explanation:

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To make the expression 4x-2 + (2x + 4) equivalent to 2(6x + 7), what must be the value in the box?
podryga [215]

4x - 2 + (2x + 4) = 2(6x + 7) \\

4x - 2 + 2x + 4 = 12x + 14

Simplification

6x + 2 = 12x + 14

Subtract sides 2

6x + 2 - 2 = 12x + 14 - 2

Simplification

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Simplification

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Divided sides by -6

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3 years ago
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statuscvo [17]

9514 1404 393

Answer:

  (a)  x = (3 -ln(3))/5 ≈ 0.819722457734

  (b)  y = 10

Step-by-step explanation:

(a) Taking the natural log of both sides, we have ...

  2x +1 = ln(3) +4 -3x

  5x = ln(3) +3 . . . . . . . . add 3x-1

  x = (ln(3) +3)/5 ≈ 0.820

__

(b) Assuming "lg" means "log", the logarithm to base 10, we have ...

  log(y -6) +log(y +15) = 2

  (y -6)(y +15) = 100 . . . . . . . taking antilogs

  y^2 -9x -190 = 0 . . . . . . . . eliminate parentheses, subtract 100

  (y -19)(y +10) = 0 . . . . . . . . factor

The values of y that make these factors zero are -19 and 10. We know from the first term that (y-6) > 0, so y > 6. That means y = -19 is an extraneous solution.

The solution is ...

  y = 10

__

When solving equations using a graphing calculator, it often works well to define a function f(x) such that the solution is f(x) = 0, the x-intercept(s). That form is easily obtained by subtracting the right side of the equation from both sides of the equation. In part (a) here, that is ...

  f(x) = e^(2x+1) -3e^(4-3x)

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X is 23/7 i think .??
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