Answer:
Gọi AH là đường cao kẻ từ A đến BC
Xét tam giác AHC vuông tại H
Suy ra AH = HC. cotA= 9.cot35° = 12,9
Xét tam giác AHB vuông tại H
Suy ra BH = AH.tanA = 12,9.tan61°=23,37
Ta có BC= HC+ HB= 9+23,27 =32,27
Diện tích tam giác ABC = 1/2 × AH ×BC= 1/2 ×12,9×32,27=208,1415
Answer:
7
Step-by-step explanation:
The order of operations tells you to start any evaluation by looking at the innermost set of parentheses first.
Here, that means your first step is to find the value of h(-3). You do that by finding the input (x) value -3 in the table for h(x), and locating the corresponding output, h(x), which is 2.
Now, the problem becomes evaluating g(2).
You do the same thing for that function: locate the input x=2 in the table for g(x) and find the corresponding output: 7.
Now, you know ...
g(h(-3)) = g(2) = 7
Substitute each value until the answer is correct
a. 1 = -4 x -5 -1
1 does not equal 19
b. 15 = -4 x 4 -1
15 does not equal -17
c. -5 = -4 x 1 -1
-5 equals -5
just to make sure the last answer is incorrect
d. -7 = -4 x 2 -1
-7 does not equal -9
Answer:
A . x= -16
Step-by-step explanation:
Answer: option a.
Explanation:
A <em>shrink</em> of a function is a <em>shrink</em> on the vertical direction. It means that for a certain value of x, the new function will have a lower value, in the intervals where the function is positive, or a higher value, in those intervals where the function is negative. This is, the image of the new function is shortened in the vertical direction.
That is the reason behind the rule:
- given f(x), the graph of the function a×f(x), when a > 1, represents a vertical stretch of f(x),
- given f(x), the graph of the function a×f(x), when a < 1, represents a vertical shrink of f(x).
So, we just must apply the rule: to find a shrink of an exponential growth function, multiply the original function by a scale factor less than 1.
Since it <em>is a shrink of</em> <em>an exponential growth function</em>, the base must be greater than 1. Among the options, the functions that meet that conditon are a and b:
Now, following the rule it is the function with the fraction (1/3) in front of the exponential part which represents a <em>shrink of an exponential function</em>.