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Oliga [24]
2 years ago
15

Jacob has a rectangular garden with an area of 56 square feet.The length of the garden is 8 feet.What is the width if the garden

?
Mathematics
1 answer:
blagie [28]2 years ago
5 0

Answer:

The width of the garden is 7 feet.

Step-by-step explanation:

If the area is 56 feet, and the length is 8 feet, we can put this into the area equation.

Area = width * length

A = wl

Substitute variables.

56 = 8w

Divide by 8.

7 = w, or w = 7.

The width of the garden is 7 feet.

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Amir stands on a balcony and throws a ball to his dog, who is at ground level.
Bumek [7]

Answer:

16 meters

Step-by-step explanation:

The height function is given by:

h(x)=-(x+1)(x-7)\\h(x)=-(x^2+x-7x-7)\\h(x)=-x^2+6x+7

The value of x, in seconds, for which the derivate of the height function is zero, is the time at which the maximum height occurs:

\frac{dh(x)}{dx}= h'(x)=-2x+6=0\\x=3

For x = 3 seconds, the height is:

h(3)=-(3^2)+6*3+7\\h(3)=16\ m

The maximum height that the ball will reach is 16 meters.

6 0
3 years ago
Read 2 more answers
Which is the completely factored form of 12x3 – 60x2 + 4x – 20?
Natalija [7]

Answer:

4(x-5)(3{x}^{2}+1)

Step-by-step explanation:

1) Find the Greatest Common Factor (GCF).

1 - What is the largest number that divides evenly into 12x^3,-60x^2,4x, and -20 ?

It is 4.

2 - What is the highest degree of x that divides evenly into 12x^3,-60x^2,4x, and -20 ?

It is 1, since x is not in every term.

3 - Multiplying the results above,

The GCF is 4.

2)  Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

4(\frac{12{x}^{3}}{4}+\frac{-60{x}^{2}}{4}+\frac{4x}{4}-\frac{20}{4})

3) Simplify each term in parentheses.

4(3{x}^{3}-15{x}^{2}+x-5)

4) Factor out common terms in the first two terms, then in the last two terms.

4(3{x}^{2}(x-5)+(x-5))

5)  Factor out the common term x-5.

4(x-5)(3{x}^{2}+1)

5 0
1 year ago
A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
3 years ago
Find the value of the missing coefficient in the factored form of 27f^3 + 125g^3. 27f^3+125g^3=(3f+5g)(9f^2-?fg + 25g)^2
7nadin3 [17]

Answer:

15

Step-by-step explanation:

The formula for factoring a sum of cubes is:

a^3+b^3=(a+b)(a^2-ab+b^2)

We have a=3f and b=5g here.

So a*b in this case is 3f*5g=15fg.

The ? is 15.

6 0
2 years ago
1/3y=3<br> Find the value of y
Ivanshal [37]
Answer is 1/9
Hope it help!!

6 0
3 years ago
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