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2 years ago

11

MY PFPPPPPPPPPPPPPPPPPPPPPP WHAT HAPPENED!???

2 answers:

rjkz [21]2 years ago

8 0

Answer:

I don't know what happened to your profile picture... I don't know if mods can remove/change pfps, but if so, then that could be the case -- especially if your pfp challenged Brainly's rules and community guidelines. Then again, it could have just been you...

Step-by-step explanation:

Alex_Xolod [135]2 years ago

7 0

it died

short answer:

R.I.P pfp

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Lady_Fox [76]

Answer:

23

Step-by-step explanation:

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3 years ago

Define a variable, write an inequality, and solve each problem. Check your solution.

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Step-by-step explanation:

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3 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

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2 years ago

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Svetlanka [38]

Answer:

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Step-by-step explanation:

8y+6y= 12y

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12y divide by 12 = 288 divided by 12 =

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2 years ago

I need help ASAP!!!Please explain how you got your answer

Naddik [55]

Answer:

See the pic below.

Step-by-step explanation:

I erased the incorrect answers and filled in the correct answers with numbers.

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