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makvit [3.9K]
3 years ago
15

SHOW that (x + 3) and (x - 2) are factors of f(x) = x4 + 10x3 + 23x2 - 34x - 120.

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
If f(x) = 0 then it is a root

x + 3 = 0
x=-3
f(-3) = (-3)^4 + 10(-3)^3 + 23(-3)^2 - 34(-3) - 120 = 0

x - 2 = 0
x=2
f(2) = (2)^4 + 10(2)^3 + 23(2)^2 - 34(2) - 120 = 0
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The points J (-13,10) and K(-1,-6) are endpoints of a diameter of circle G. What is the equation of circle G?
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The correct answer is D

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to find (h,k), you find the middle of the circle, in this scenario you do so by finding the middle of the diameter, a line that goes through the center of the circle.

To find the X value of the midpoint, add both x values together and divide by 2 and repeat for y

-13 + -1 = -14
-14/2 =-7

10+ -6 = 4
4/2 = 2

therefore (h,k) = ( -7, 2 )

Next plug these values in the equation of a circle

(x-h)^2 + (y-k)^2 = r^2

becomes

(x- (-7)) ^2 + (y-(2)) ^2 = r^2

to find r, use the distance formula to find the length of the diameter, 20, and divide by 2


plug 10 in for r and you get 100

(x+7)^2 + (y-2)^2 = 100

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