4. At Lilly's Bakery, the ideal weight of a loaf of bread is 24 ounces. By law, the actual weight can vary from

Solve the equation 2x^{2}+9x-1=x to the nearest 10th

Scilla [17]

Answer:

2x2+9x−1=x

Step 1: Subtract x from both sides.

2x2+9x−1−x=x−x

2x2+8x−1=0

Step 2: Use quadratic formula with a=2, b=8, c=-1.

x=

−b±√b2−4ac

2a

x=

−(8)±√(8)2−4(2)(−1)

2(2)

x=

−8±√72

4

x=−2+

3

2

√2 or x=−2+

−3

2

√2

Step-by-step explanation:

This is what I got but I'm not 100% positive. I checked it on a calculator and it seemed to check out.

4 0

4 years ago

Can u answer number 10?

KonstantinChe [14]

5.7(0.59)= B
2.8(1.99)= A

8 0

3 years ago

Regular hexagon ABCDEF has vertices at A(4, 4!3), B(8, 4!3), C(10, 2!3), D(8, 0), E(4, 0) and F(2, 2!3).

marissa [1.9K]

Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:

$A=\frac{3\sqrt{3}}{2} a^2$

Where $A$ is the area of the regular hexagon

$a$ is the side length of the regular hexagon

Also, it's Perimeter is given by:

$P=6a$

Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.

A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Where $d$ is the distance.

$(x_1,y_1)$ and $(x_2,y_2)$ are the coordinates of points D and E respectively. (please note that interchanging the values of the coordinates will not alter the distance $d$ )