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leonid [27]
3 years ago
13

The volume of the rectangular prism is 90 cubic feet. What is the height of the rectangular prism?

Mathematics
1 answer:
shusha [124]3 years ago
8 0

Answer:

6

Step-by-step explanation:

3*5*height=90

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Rewrite the function by completing the square. 4x^2-4x+1=0
andrey2020 [161]

Do in <u>completing the square method.</u>

{4x}^{2}  - 4x + 1 = 0 \\ 4x^{2}-4x=-1  \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4}  \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4}  \\ x^{2}-x=\frac{-1}{4}  \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2}  \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4}  \\ x^{2}-x+\frac{1}{4}=0  \\ \left(x-\frac{1}{2}\right)^{2}=0  \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0}

Now simplify.

x-\frac{1}{2}=0 \\  x-\frac{1}{2}=0  \\  \\  \rightarrow \: x=\frac{1}{2}  \\  \rightarrow \: x=\frac{1}{2}

So, answer is..

\boxed{x=\frac{1}{2} }

Now <u>rewrite</u> the equation.

4 x ^ { 2 } - 4 x + 1 = 0 \\  \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  }

<u>Verification :-</u>

4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-\frac{4}{2}+1=0  \\ 1-2+1=0  \\ -1+1=0  \\ \underline{ 0 = 0} \:  \\  \dashrightarrow \text{true}

3 0
3 years ago
Help does anybody no this I've been sick on this question for hours?? Number 18.
ANTONII [103]
You just have to divide the bigger x value by the smaller x value
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4 0
4 years ago
Given the polynomial f(x)=8x5−4x3 6x 15
Aleonysh [2.5K]
Hello,

Answer D 5/4


since div 15={1,3,5,15}
and div 8={1,2,4,8}
posiible rational root is a*b where a∈div 15 and b∈div 8

6 0
3 years ago
Solve for x &amp; y solve x = 3 + yy = -2x + 9
sergey [27]

x = 3 + y Eqn(1)

y = -2x + 9​ Eqn(2)

Let us solve the system of equations with the substitution method

x - 3 = y (Subtracting 3 from both sides of the Eqn(1))

Replacing y = x - 3 in Eqn (2), we have:

x - 3 = -2x + 9

x = -2x + 9 + 3 (Adding 3 to both sides of the equation)

x + 2x = 9 + 3 (Adding 2x to both sides of the equation)

3x = 12 ( Adding like terms)

x = 12/3 (Dividing by 3 on both sides of the equation)

x = 4

Replacing x=4 in Eqn(1), we have:

4 = 3 + y

4 - 3 = y (Subtracting 3 from both sides of the equation)

y=1

The answers are:

x= 4 and y=1

6 0
1 year ago
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