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wlad13 [49]
3 years ago
14

Quadrants on the coordinate plane Select the quadrant or axis where each ordered pair is located on a coordinate plane. Quadrant

Quadrant II Quadrant III Quadrant IV I-axis y-axis (-9.-8) (1.0) (7.5.2 Stuck? Watch a video or use a hint. Report a problem​
Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0

Answer:

lll

Step-by-step explanation:

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In an arithmetic​ sequence, the nth term an is given by the formula an=a1+(n−1)d​, where a1 is the first term and d is the commo
Dmitry_Shevchenko [17]

Answer:

a_{10} = \frac{10}{65536}

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

a_{3} - a_{2} = a_{2} - a_{1}

We have that:

a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}

a_{3} - a_{2} = a_{2} - a_{1}

\frac{5}{2} - 10 = 10 - 40

\frac{-15}{2} \neq -30

This is not an arithmetic sequence.

This sequence is geometric if:

\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}

\frac{\frac{5}[2}}{10} = \frac{10}{40}

\frac{5}{20} = \frac{1}{4}

\frac{1}{4} = \frac{1}{4}

This is a geometric sequence, in which:

The first term is 40, so a_{1} = 40

The common ratio is \frac{1}{4}, so r = \frac{1}{4}.

We have that:

a_{n} = a_{1}*r^{n-1}

The 10th term is a_{10}. So:

a_{10} = a_{1}*r^{9}

a_{10} = 40*(\frac{1}{4})^{9}

a_{10} = \frac{40}{262144}

Simplifying by 4, we have:

a_{10} = \frac{10}{65536}

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Answer:

yes

Step-by-step explanation:

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Question 5: perform without writing vertically<br>a) 50 x 513 x 2<br>how we can solve it​
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